anonymous
  • anonymous
Suppose angle A=pi/4 radians and length of b=3
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
anonymous
  • anonymous
since angle a is pi/4 radians angle a is 45 degrees
anonymous
  • anonymous
and angle b is 45 degrees

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hartnn
  • hartnn
ohh i like pi/4 angle the angles become congruent and 2 sides become equal :P
anonymous
  • anonymous
:D I set up tan45=a/3
anonymous
  • anonymous
and got that a=3
hartnn
  • hartnn
correct
anonymous
  • anonymous
since it's a 45-45-90 triangle a and b are both 3
hartnn
  • hartnn
agreed
anonymous
  • anonymous
so 3^2+3^2=c^2, 9+9=c^2, 18=c^2 i'm not sure if we need to get square root of 18
hartnn
  • hartnn
ok, lets use a trig function then find sin A or sin B
anonymous
  • anonymous
so sin(45)=3/c, c=3*sin45 which is 2.12
hartnn
  • hartnn
you can keep it as \(3/ \sqrt 2\)
anonymous
  • anonymous
where did we get the 3/sqrt of 2 from? lol
hartnn
  • hartnn
because it is mentioned, "no decimals"
hartnn
  • hartnn
sin 45 = 1/\(\sqrt 2\) 3 sin 45 = 3/\(\sqrt 2\)
anonymous
  • anonymous
sin of 45 =sqrt(2)/2..
hartnn
  • hartnn
|dw:1443980994981:dw|
anonymous
  • anonymous
hmm a little confused why we are multiplying by 2 :/
hartnn
  • hartnn
we're braking 2 as \(\sqrt 2 \times \sqrt 2 \) if thats confusing you, you can keep the answer as \(3\sqrt 2/2 \) also
anonymous
  • anonymous
so the length of a should be 3,
hartnn
  • hartnn
length of a was always 3... i though we were talking about length of c
anonymous
  • anonymous
Yea I'm just clarifying :)
anonymous
  • anonymous
and length of c=3sqrt(2)/2?
anonymous
  • anonymous
for some reason it's saying that c isn't correct
hartnn
  • hartnn
try 3/ \(\sqrt 2\) once?
anonymous
  • anonymous
so since I got it wrong it gave me the same problem expect a=6
hartnn
  • hartnn
oh wait! sin A = a/c c = a/ sin A = 3/ sin 45 = 3 sqrt 2 :P
hartnn
  • hartnn
now it'll be 6 sqrt 2
hartnn
  • hartnn
\(6\sqrt 2\)
anonymous
  • anonymous
and b would just equal 6 because they are 45-45-90
hartnn
  • hartnn
correct!
anonymous
  • anonymous
yay :D it's right thank you
Mertsj
  • Mertsj
Since it is an isosceles triangle and b = 3, then a = 3 and the hypotenuse= 3sqrt2 and both A & B are pi/4 radians
hartnn
  • hartnn
^^
anonymous
  • anonymous
Mertsj, thank you for the information :)
Mertsj
  • Mertsj
yw

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