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since angle a is pi/4 radians angle a is 45 degrees
and angle b is 45 degrees
ohh i like pi/4 angle the angles become congruent and 2 sides become equal :P
:D I set up tan45=a/3
and got that a=3
since it's a 45-45-90 triangle a and b are both 3
so 3^2+3^2=c^2, 9+9=c^2, 18=c^2 i'm not sure if we need to get square root of 18
ok, lets use a trig function then find sin A or sin B
so sin(45)=3/c, c=3*sin45 which is 2.12
you can keep it as \(3/ \sqrt 2\)
where did we get the 3/sqrt of 2 from? lol
because it is mentioned, "no decimals"
sin 45 = 1/\(\sqrt 2\) 3 sin 45 = 3/\(\sqrt 2\)
sin of 45 =sqrt(2)/2..
hmm a little confused why we are multiplying by 2 :/
we're braking 2 as \(\sqrt 2 \times \sqrt 2 \) if thats confusing you, you can keep the answer as \(3\sqrt 2/2 \) also
so the length of a should be 3,
length of a was always 3... i though we were talking about length of c
Yea I'm just clarifying :)
and length of c=3sqrt(2)/2?
for some reason it's saying that c isn't correct
try 3/ \(\sqrt 2\) once?
so since I got it wrong it gave me the same problem expect a=6
oh wait! sin A = a/c c = a/ sin A = 3/ sin 45 = 3 sqrt 2 :P
now it'll be 6 sqrt 2
and b would just equal 6 because they are 45-45-90
yay :D it's right thank you
Since it is an isosceles triangle and b = 3, then a = 3 and the hypotenuse= 3sqrt2 and both A & B are pi/4 radians
Mertsj, thank you for the information :)