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anonymous

  • one year ago

If you were asked to convert 4.2 X 10^22 atoms of aluminum to moles, which of the following should you use for the conversion?

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  1. imqwerty
    • one year ago
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    \[\frac{ 4.2 \times 10^{22}}{ N_{A} }\] N_{A} is the avagadro number

  2. imqwerty
    • one year ago
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    yea sure :)

  3. imqwerty
    • one year ago
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    1mole of any substance has 6.022 x 10^23 particles of it

  4. imqwerty
    • one year ago
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    so 1 mole of Al has 6.022 x 10^23 atoms

  5. Mertsj
    • one year ago
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    well which one of those is true? is 6.023x10^23 atoms of Al equal to 13 moles Al

  6. imqwerty
    • one year ago
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    now if 1 mole has 6.022 x 10^23 atom then how many mole will have 4.2 x 10^22 atoms :)

  7. imqwerty
    • one year ago
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    can u calculate how many moles will have 1 atom?

  8. imqwerty
    • one year ago
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    well just because it has that bad number 26.891... we can't say its wrng we have to give proper reasoning ok we know that 1mole has 6.022 x 10^23 particles we need to find how many moles will have 1 particle so 1st answer this- 6 bags have 3 chocolates how many bags will have 1 chocolate?

  9. wolf1728
    • one year ago
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    What's with the mass of aluminum? The origianl question just want number of moles.

  10. imqwerty
    • one year ago
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    ur saying B is correct cause it has got mass/ nvm its ok :)

  11. wolf1728
    • one year ago
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    But the original question was just "how many moles is 4.2 x 10^22 atoms".

  12. wolf1728
    • one year ago
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    There are 6.023 x 10^23 atoms per mole. You have 4.2 x 10^22 atoms. 4.2 x 10^22 * 1 mole/6.023 x 10^23 atoms

  13. imqwerty
    • one year ago
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    yes

  14. wolf1728
    • one year ago
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    Or number 4 in your list

  15. wolf1728
    • one year ago
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    sure

  16. wolf1728
    • one year ago
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    2.03 X 10^24 atoms * 1 mole/6.023 x 10^23

  17. wolf1728
    • one year ago
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    Look carefully at my answer. You don't multiply both numbers.

  18. imqwerty
    • one year ago
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    number of moles = no of atoms /avagadro number :)

  19. wolf1728
    • one year ago
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    I made a graphic which shows the calculation more clearly:

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  20. imqwerty
    • one year ago
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    yes :D

  21. wolf1728
    • one year ago
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    B it is!!

  22. wolf1728
    • one year ago
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    okay 1 more question.

  23. imqwerty
    • one year ago
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    np B)

  24. imqwerty
    • one year ago
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    moles=mass/molar mass molar mass of silver=108

  25. imqwerty
    • one year ago
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    yea correct :D

  26. wolf1728
    • one year ago
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    Remember to learn how to set it up correctly. What if you set it up as 107.9/68.3?

  27. wolf1728
    • one year ago
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    Yes you set it up the right way 68.3/107.9 but you will have to see why.

  28. wolf1728
    • one year ago
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    The important thing is if you know the correct way to set up the answer because I'm assuming you will be tested on this, right?

  29. wolf1728
    • one year ago
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    So then you will definitely have to learn how to set up the answer.

  30. wolf1728
    • one year ago
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    Well imqwerty and myself looked at the answers and we're sure they are correct.

  31. wolf1728
    • one year ago
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    Atomic mass of copper = 63.55 meaning there are 6.023 x 10^23 atoms for every 63.55 grams of copper. We need to know atoms in 68.7 grams of copper: 68.7 * 6.023 x 10^23 atoms / 63.55 grams copper = 6.511 x 10^23 atoms which is C which is your answer

  32. wolf1728
    • one year ago
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    Moles in 125 g of NI atomic mass Ni = 58.71 grams per mole 125 grams * 1 mole / 58.71 grams = 2.129 moles B (which is your answer)

  33. imqwerty
    • one year ago
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    #( 1mole of silver=108gm=6.022x10^23 particles \[\frac{ 108\times 5.8 \times 10^{23} }{ 6.022 \times 10^{23}}=mass of (5.8 \times 10^{23})particles\]

  34. imqwerty
    • one year ago
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    ^#9

  35. wolf1728
    • one year ago
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    I'm working on number 8

  36. wolf1728
    • one year ago
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    It seems to me you just want correct answers as opposed to HOW to set up the answers. Question 8 - your answer is wrong. What is the mass of 25 atoms of mercury? (your answer)

  37. imqwerty
    • one year ago
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    yes sofia :) thas correct

  38. wolf1728
    • one year ago
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    So what is your answer for #8?

  39. imqwerty
    • one year ago
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    np :) sofia can u tell how did u find out the mass

  40. imqwerty
    • one year ago
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    nvm :) tell ur method

  41. wolf1728
    • one year ago
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    Yes it is either B or C for #8

  42. imqwerty
    • one year ago
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    yes

  43. imqwerty
    • one year ago
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    ok :)

  44. imqwerty
    • one year ago
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    yes :D

  45. imqwerty
    • one year ago
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    np (:

  46. wolf1728
    • one year ago
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    Did you figure out #8 yet?

  47. wolf1728
    • one year ago
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    Yes it is C - very good!

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