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zned6559
 one year ago
Calculate lim t> negative infinity ((2t^2  t 2)^1/2) / (2t+1)
zned6559
 one year ago
Calculate lim t> negative infinity ((2t^2  t 2)^1/2) / (2t+1)

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amistre64
 one year ago
Best ResponseYou've already chosen the best response.2x = sqrt(x^2) ... might be useful

zned6559
 one year ago
Best ResponseYou've already chosen the best response.0I know the answer is 1/sqrt 2 but I don't know how to get there

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2^(1/2) is the same as sqrt() id put them both under the sqrt and compare them

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{\sqrt{2t^2t1}}{\sqrt{(2t+1)^2}}\]

zned6559
 one year ago
Best ResponseYou've already chosen the best response.0the bottom is suppose to be 2t+1 no sqrt

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2what does sqrt(x^2) reduce to?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2then sqrt((2t+1)^2) = 2t+1

zned6559
 one year ago
Best ResponseYou've already chosen the best response.0\[\sqrt{2t ^{2}t2}\div2t+1\]

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2you are not seeing the obvious ... \[\sqrt{2t ^{2}t2}\div2t+1\] \[\sqrt{2t ^{2}t2}\div \sqrt{(2t+1)^2}\]

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2what is the expansion of (2t+1)^2 ?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2then we have \[\sqrt{\frac{2t^2t2}{4t^2+4t+1}}\]

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2what do we know about polynomials and their limits?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2then you need to cover some of your basic rules .... not sure what theyve covered tho

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2polys of the same degree, limit to their leading coeffs

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2the only thing to watch for is the sign, by squaring the bottom we altered the sign of it inthe process.

amistre64
 one year ago
Best ResponseYou've already chosen the best response.22t+1 as t to inf is a negative value .... so we are originally going to have a negative limit in the end
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