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anonymous

  • one year ago

suppose angle B=60 degrees, and length of b=2

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  1. anonymous
    • one year ago
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  2. hartnn
    • one year ago
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    what have you tried? :)

  3. anonymous
    • one year ago
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    angle a is 30 degrees

  4. anonymous
    • one year ago
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    which means b is 60 degrees

  5. hartnn
    • one year ago
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    A=30 is correct, B = 60 is given, go on

  6. anonymous
    • one year ago
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    tan30=a/2

  7. anonymous
    • one year ago
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    2*tan(30)=a/2

  8. hartnn
    • one year ago
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    a =2 tan 30

  9. anonymous
    • one year ago
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    which is 1.15 which is just 1

  10. anonymous
    • one year ago
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    they want the exact measures

  11. hartnn
    • one year ago
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    since we are not allowed decimals, whats tan 30 in fraction ?

  12. anonymous
    • one year ago
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    1/sqrt3

  13. hartnn
    • one year ago
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    or lets try to get 'c' first using sin B

  14. hartnn
    • one year ago
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    ok, thats correct, so a = 2/\sqrt 3

  15. hartnn
    • one year ago
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    \(a= \dfrac{2}{\sqrt 3 }\)

  16. anonymous
    • one year ago
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    so sin60=2/c, 2*sin60,

  17. anonymous
    • one year ago
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    sin of 60 degrees is sort(3)/2

  18. anonymous
    • one year ago
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    sqrt*

  19. hartnn
    • one year ago
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    yes sqrt 3/2 = 2/c so c = 2*2/ sqrt 3 = ...

  20. anonymous
    • one year ago
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    4/sqrt(3)

  21. hartnn
    • one year ago
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    \(\huge \checkmark \)

  22. anonymous
    • one year ago
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    so basically we are transforming the degrees into the coordinates of either sin or cos .. i'm slow :)

  23. hartnn
    • one year ago
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    i didn't get that :P we are trying to find the missing angles and sides of a triangles using sin/cos/tan ....

  24. anonymous
    • one year ago
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    but every coordinate on the unit circle has either a sin and cos.. just clarifying :D

  25. hartnn
    • one year ago
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    yes, that is true!

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