## zned6559 one year ago Find the equation to the tangent line to the curve x^2 (2-x)-y^2 =0

1. zned6559

$x ^{2}(2-x) - y ^{2}$

2. anonymous

$y=\sqrt{2x^2-x^3}$

3. anonymous

$\frac{ dy }{ dx }=\frac{ 1\left( 4x-3x^2 \right) }{ 2\sqrt{2x^2-x^3} }$

4. anonymous

find x,and then y eq. of tangent is y-?=dy/dx(x-?)