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vheah

  • one year ago

Electron Configuration question: How do you write the electron configuration if an Element has a charge? Example: V^5+ I heard that p and s blocks get taken off respectively before the d block. But how would it look like?

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  1. aaronq
    • one year ago
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    you remove electrons that are higher in energy (e.g. 4s electrons before 3d electrons) so for vanadium, you have \(\sf [Ar]3d^34s^2\) you remove the 2 4s elctrons and the 3 3d electrons, leaving with you just the electronic configuration of Ar.

  2. vheah
    • one year ago
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    Thanks. So you remove s electrons and d next? What about the p electrons?

  3. aaronq
    • one year ago
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    the 3p electrons would be next, but it's not really common for vanadium to lose some many electrons because it would take too much energy.

  4. vheah
    • one year ago
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    Okay. I think I got it. Thanks!

  5. aaronq
    • one year ago
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    No problem. If you have another example you can post what you think the answer is and i can check it.

  6. vheah
    • one year ago
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    Will do :)

  7. vheah
    • one year ago
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    Let's say it's Ni2+ would the electron config be [Ar]3d^8 ?

  8. aaronq
    • one year ago
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    yes

  9. aaronq
    • one year ago
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    \(\huge \checkmark\)

  10. vheah
    • one year ago
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    Yeeey. Thanks a lot. I think i got it now :)

  11. aaronq
    • one year ago
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    sweeet, no problemssss

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