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for it to hit the ground the height must be zero
I don't understand your function
but pretend we have the height is h h(t)=5t^2+t and we want to know when h is 0 replace h(t) with 0 0=5t^2+t and solve for t
that is correct for the example function I gave
can't be 0 doesn't make sense
but as I said I do not understand what your function is
its for a class i didnt write it a teacher did
write it out using the equation thing
she really wrote "=h−140−8t16t2 " because this makes no sense
ok replace h with 0
since we are given the height is 0
and you are looking for the second 0 not the first 0
then solve for t using factoring or quadratic formula
A ball is thrown from a height of 140 feet with an initial downward velocity of 8/fts . The ball's height h (in feet) after t seconds is given by the following.
I think your copying and pasting is not working :p
but anyways you already corrected your function for h so we know it now can you replace h with 0 and solve for t?
ok thnaks =)
t=2.72 or t=-3.22
those are approximately right and you should be looking for the second zero that zero being t=2.72 (since this occur later)