A ball is thrown from a height of
140
feet with an initial downward velocity of
8/fts
. The ball's height
h
(in feet) after
t
seconds is given by the following.
=h−140−8t16t2
How long after the ball is thrown does it hit the ground?

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- anonymous

- schrodinger

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- freckles

for it to hit the ground the height must be zero

- freckles

I don't understand your function

- freckles

but pretend we have the height is h
h(t)=5t^2+t
and we want to know when h is 0
replace h(t) with 0
0=5t^2+t
and solve for t

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## More answers

- anonymous

t=0,-1/5 @freckles

- freckles

that is correct for the example function I gave

- Ac3

can't be 0 doesn't make sense

- freckles

but as I said I do not understand what your function is

- anonymous

its for a class i didnt write it a teacher did

- Ac3

write it out using the equation thing

- freckles

she really wrote "=h−140−8t16t2
"
because this makes no sense

- anonymous

h=140-8t-16t^2

- Ac3

ohhhh

- freckles

ok replace h with 0

- freckles

since we are given the height is 0

- freckles

and you are looking for the second 0 not the first 0

- Ac3

then solve for t using factoring or quadratic formula

- anonymous

A ball is thrown from a height of
140
feet with an initial downward velocity of
8/fts
. The ball's height
h
(in feet) after
t
seconds is given by the following.

- freckles

I think your copying and pasting is not working :p

- freckles

but anyways you already corrected your function for h
so we know it now
can you replace h with 0 and solve for t?

- anonymous

ok thnaks =)

- anonymous

t=2.72 or t=-3.22

- freckles

those are approximately right
and you should be looking for the second zero
that zero being t=2.72 (since this occur later)

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