A ball is thrown from an initial height of 1 meter with an initial upward velocity of 25/ms.The ball's height h (in meters) after t seconds is given by the following. h=1+25t-5t^2 Find all values of t for which the ball's height is 6 meters.
Round your answer(s) to the nearest hundredth.
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@kamelish Can you draw the picture and write down the given data, like \(h=?\) etc ...
it wont let me @Koikkara
\[ h=1+25t-52t^2 \]
ball's height is 6 . That means h is 6.
\[ 6 = 1+25t-52t^2 \]
put that in standard form
\[ -52t^2 +25t -5=0 \]
It looks like we should use the quadratic formula to solve for t
do you know the quadratic formula?
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its 5t^2 i made a mistake @phi
that's good, a much nicer number
\[ -5t^2 +25t+1=6 \\ -5t^2 + 25t -5= 0 \]
divide both sides by -5 (to simplify the equation a little bit)
\[ t^2 -5t+1=0\]
but you still need to use the quadratic formula. Do you know it ?
i know it a little bit @phi
Do you have time to see this
It is pretty good.
t=4.79 or t=0.20? @phi
if you have multiple choice, you can test each answer in the original formula
\[ 1+25t-5t^2 = 6 \]
and see if you get 6 for the left-hand side