anonymous
  • anonymous
exact measures
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
hartnn
  • hartnn
how did u get b as that?
hartnn
  • hartnn
try to find sin A you won't find b there at all :P

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Ac3
  • Ac3
use tangent to find side b
Ac3
  • Ac3
doesn't matter which angle you pick you'll get it right either way
anonymous
  • anonymous
so there's my mistake,.. tan82=5/b
Ac3
  • Ac3
just remember tangent= opp/adj
hartnn
  • hartnn
yep, thats correct find b from there
anonymous
  • anonymous
b=5tan(82)
Ac3
  • Ac3
so b = 5/tan(82)
Nnesha
  • Nnesha
|dw:1443988627702:dw| remember \[\rm sin \rm \theta = \frac{ opposite }{ hypotenuse }~~~~ \cos \theta = \frac{ adjacent }{ hypotenuse } ~~\tan \theta = \frac{ opposite }{ adjacent }\] if you want to find hypotenuse then you should use sin A =opposite/hyp
Ac3
  • Ac3
your not solving for b properly you have to multiply both sides by b then divide by tan(82) bot sides
Nnesha
  • Nnesha
|dw:1443988722622:dw| given is opposite side of angle A and we want to find b which ration equal to opposite over adjacent
hartnn
  • hartnn
tan 82 = 5/b b*tan 82 = 5 b = 5/tan 82
anonymous
  • anonymous
oh i see
anonymous
  • anonymous
to find the length of c I believe you would set up cos90=5/c
hartnn
  • hartnn
you mean cos 8 = 5/c ??
Nnesha
  • Nnesha
she is using right angle
hartnn
  • hartnn
cos 90 = sin 0 = 0
hartnn
  • hartnn
if its 5/c its cos 8 or sin 82
Nnesha
  • Nnesha
|dw:1443988964305:dw| to find length C u don't have to use angle C use A or B
anonymous
  • anonymous
hartnn where did you get the 8 from? :)
anonymous
  • anonymous
hartnn never mind the angle :D
hartnn
  • hartnn
8 is the angle of B in degrees
hartnn
  • hartnn
but lets use sin 82 because 82 is a given information
anonymous
  • anonymous
ok :) makes sense so sin82=5/c
hartnn
  • hartnn
good, find c
anonymous
  • anonymous
5/sin82
hartnn
  • hartnn
excellent! you didn't repeat the same mistake :)
anonymous
  • anonymous
I have a good teacher :D
hartnn
  • hartnn
*blushes* :P i have an amazing student :)
anonymous
  • anonymous
:-)

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