## anonymous one year ago exact measures

1. anonymous

2. hartnn

how did u get b as that?

3. hartnn

try to find sin A you won't find b there at all :P

4. Ac3

use tangent to find side b

5. Ac3

doesn't matter which angle you pick you'll get it right either way

6. anonymous

so there's my mistake,.. tan82=5/b

7. Ac3

8. hartnn

yep, thats correct find b from there

9. anonymous

b=5tan(82)

10. Ac3

so b = 5/tan(82)

11. Nnesha

|dw:1443988627702:dw| remember $\rm sin \rm \theta = \frac{ opposite }{ hypotenuse }~~~~ \cos \theta = \frac{ adjacent }{ hypotenuse } ~~\tan \theta = \frac{ opposite }{ adjacent }$ if you want to find hypotenuse then you should use sin A =opposite/hyp

12. Ac3

your not solving for b properly you have to multiply both sides by b then divide by tan(82) bot sides

13. Nnesha

|dw:1443988722622:dw| given is opposite side of angle A and we want to find b which ration equal to opposite over adjacent

14. hartnn

tan 82 = 5/b b*tan 82 = 5 b = 5/tan 82

15. anonymous

oh i see

16. anonymous

to find the length of c I believe you would set up cos90=5/c

17. hartnn

you mean cos 8 = 5/c ??

18. Nnesha

she is using right angle

19. hartnn

cos 90 = sin 0 = 0

20. hartnn

if its 5/c its cos 8 or sin 82

21. Nnesha

|dw:1443988964305:dw| to find length C u don't have to use angle C use A or B

22. anonymous

hartnn where did you get the 8 from? :)

23. anonymous

hartnn never mind the angle :D

24. hartnn

8 is the angle of B in degrees

25. hartnn

but lets use sin 82 because 82 is a given information

26. anonymous

ok :) makes sense so sin82=5/c

27. hartnn

good, find c

28. anonymous

5/sin82

29. hartnn

excellent! you didn't repeat the same mistake :)

30. anonymous

I have a good teacher :D

31. hartnn

*blushes* :P i have an amazing student :)

32. anonymous

:-)