anonymous
  • anonymous
Find the mass in grams of 2.00*10^23 molecules of F2.
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[2.00 \times 10^{23} molecules F _{2} \times \frac{ 1mol F _{2} }{ 6.023 \times 10^{23} molecules F _{2} } \times \frac{ 38.00 g F _{2} }{ 1mol F _{2} }\]
anonymous
  • anonymous
1molF2, would that be the atomic mass or Fluorine times 2?
anonymous
  • anonymous
Yep. 1 mole is atomic mass.

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anonymous
  • anonymous
would the answer be 1.26*10^47?
anonymous
  • anonymous
If you calculated it right, it would be.
anonymous
  • anonymous
Okay, thank you very much!!
anonymous
  • anonymous
Doenst look like it to me. It should be less.
anonymous
  • anonymous
It should be way way less. The grams should be less than 38 grams.
anonymous
  • anonymous
on my calculator I typed in 2.00*10^23 x 37.996/6.022*10^23 x 38.00/37.996 = 1.26203919*10^47
anonymous
  • anonymous
Where are you getting those numbers? Use my dimensional analysis. As you can see the given unit is canceled out and the mass unit (grams) is left. No need to add anything.
anonymous
  • anonymous
I did use it. I replace 1molF2 w/ 37.996, thats the only thing that is different!
anonymous
  • anonymous
I got that by doing: (2*18.998) = 37.996
anonymous
  • anonymous
Close enough to be 38.00 gram. Thats why I put it on top of mole. 1 mole F2=38.00 grams F2 You dont replace anything in this conversion. You can but its not necessary. Just makes everything longer. And you are not entering it in the calculator right because of the unnecessary steps. (2.00 x 10^23/6.023 x 10^23) x 38.00 This is just basic operations.
anonymous
  • anonymous
okay well thank you
anonymous
  • anonymous
No problem!

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