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so do you know able the exact value ratios in trigonometry...?

yes the sin, cos and tan

I get the proportions mixed up!

for a i got 5sin30

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Use
$$
\sin 60^\circ =\cfrac{\sqrt 3}{2}\\
\sin 30^\circ =\cfrac{ 1}{2}\\
$$

ybarrap, how would I solve based off of the proportion.. it's a little confusing for me

I bailed early because of the flood of information

Mertsj, it's more easier for me when I actually set up proportions

according to the previous question: you should include sin cos and tan ratios in your answer

Nnesha, I'm not sure if i'm setting up the proportion up for a correctly. I wrote a=sin30

a=5sin30*

That is using trig. For "special triangles"
30-60-90
and 45-45-90
people memorize some "short cuts"

Are you studying trig or "special triangles" ?

ok thank you :) for the length of b I got 5sqrt(3)/2 not sure if it's correct

I'm studying trig

yes, b is \(5\sqrt3/2\)
cos 30 = b/c
sin 60 = b/c
either way, with c=5, you will get b= 5 sqr(3)/2

got it thank you phi!

if you have time, get some popcorn and watch Khan's videos

thanks for the advice :D definitely will do!