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Compassionate
 one year ago
Easiest way to graph an equation?
Compassionate
 one year ago
Easiest way to graph an equation?

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Compassionate
 one year ago
Best ResponseYou've already chosen the best response.0Say I have an equation in y = mx + b ... Lets ay, y = 2x + 4

Compassionate
 one year ago
Best ResponseYou've already chosen the best response.0yintercept = 4, so I would graph 4 on the yaxis Now, my slope is 2x, so I could just graph 2? Or would I have to plug in values for 2, like x = 1 x = 0 x = 1 or will just graphing 2 be enough?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2slope = rise over run and you can write 2 as 2/1 \[\huge\rm slope =\frac{ rise }{ run }\]

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1And I thought the easiest way was to use technology can you graph y = x/(x^2 + 1) using this method

Compassionate
 one year ago
Best ResponseYou've already chosen the best response.0Right, so would I calculate my slope from my yintercept.

Compassionate
 one year ago
Best ResponseYou've already chosen the best response.0Let's stick to linear equations @campbell_st , all those hyperboles and binomials don't sit well with me

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1well I'd still say technology is the easiest method is if its only straight lines

Compassionate
 one year ago
Best ResponseYou've already chosen the best response.0If only I could use graphing technology on standardized testing

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2yes right first draw a point on yaxis (yintercept) and btw slope is just 2 x is a variable not slope dw:1443991125916:dw

Compassionate
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443991206348:dw

Compassionate
 one year ago
Best ResponseYou've already chosen the best response.0so it would look something like this?

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1don't forget you should choose 3 independent values.... to avoid errors

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1but what if the line has no slope...

Compassionate
 one year ago
Best ResponseYou've already chosen the best response.0X is independent, right? y = 2x + 4 y = 2(1) + 4 y = 6 y = 2(2) + 4 y = 8 y = 2(3) + 4 y = 10 Like that?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2dw:1443991283848:dw looks good to me but to draw a perfect line you can go down down left one as wll

Compassionate
 one year ago
Best ResponseYou've already chosen the best response.0If the line had no slope, say y = 4 Wouldn't I just graph a horizontal line across the yaxis, since it has no point of intersection on the xaxis? A line with no slope is either parallel to x when y = a number, or parallel to y when x = a number

Compassionate
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443991488766:dw

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1why not graph the line using intercepts.. y = 2x + 4 x intercept 2 when y = 0 and y intercept 4 when x = 0 that's an easy method

idku
 one year ago
Best ResponseYou've already chosen the best response.0y=mx+b 0=mx+b > b=mx > b/m=x point: (b/m, 0) y=m(0)+b > y=b point: (0,b) Graph the points (0, b) and (b/m, 0) and connect them with a ruler.

Compassionate
 one year ago
Best ResponseYou've already chosen the best response.0You guys are confusing me with al these different methods.

idku
 one year ago
Best ResponseYou've already chosen the best response.0just extract two points (intercepts are easier to find), and connect the dots. This is all.

Compassionate
 one year ago
Best ResponseYou've already chosen the best response.0y = 2x + 4 0 = 2x + 4  4 = 2x x = 2 Then y = 0 + 4 y = 4 So I can graph (2, 0), (0, 4) Then that will give me bot the intercepts. I get it.

idku
 one year ago
Best ResponseYou've already chosen the best response.0and connect intercepts (after you graph them) with a ruler.

Compassionate
 one year ago
Best ResponseYou've already chosen the best response.0What if I'm given two equations to graph now. Say y = 2x + 4 6x  3x = y And one of my equations isn't in y = mx + b, should I convert my second equation to y = mx + b or what?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2to graph an equation we dont' really need to find intercepts but you CAN if you want

idku
 one year ago
Best ResponseYou've already chosen the best response.0well, you can use a graphing calculator, but it is not called you graphing it....

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2yes first you have to rewrite the equation in slope intercept

idku
 one year ago
Best ResponseYou've already chosen the best response.0the easiest I would do, when I have a y=mx+b to graph, 1) Find y and x intercepts 2) Graph these two points (the y and x intercepts you have found) 3) Connect the intercepts with a rule Bam!

Compassionate
 one year ago
Best ResponseYou've already chosen the best response.0y = 2x + 4 6x  3 = y Now, what if I solve it... Like y = 2x + 4 y = 6x + 4 Is that right?

idku
 one year ago
Best ResponseYou've already chosen the best response.0you want to solve the system, right?

Compassionate
 one year ago
Best ResponseYou've already chosen the best response.0WEll, I Want to graph it

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2both equations are already in slope intercept form :D

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2i guess there is a typo are you sure it's `6x3x`=y ?

idku
 one year ago
Best ResponseYou've already chosen the best response.0y = 2x + 4 6x  4 = y multiply equation#2 times 1. y = 2x + 4 6x + 4 = y now we will do addition to eliminate the y. y = 2x + 4 y = 6x + 4  0 = 4x + 8

idku
 one year ago
Best ResponseYou've already chosen the best response.0I guess it was 4 in eq2?

Compassionate
 one year ago
Best ResponseYou've already chosen the best response.0y = 2x + 4 6x  4 = y Why not just 6x  4 = 2x + 4 4x = 8 x = 2 y = 2(2) + 4 y = 4 + 4 y = 8 So, (2, 8) would be the point of intersection, right? That's where the two lines cross.

idku
 one year ago
Best ResponseYou've already chosen the best response.0I for some reason prefered elimination

Compassionate
 one year ago
Best ResponseYou've already chosen the best response.0If I wanted to graph the lines, would I just put them both in y = mx+ b and just use the aforementioned method to just graph each line individually?

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1perhaps you can graph them to check... that's easy

Compassionate
 one year ago
Best ResponseYou've already chosen the best response.0If I graph them and my point of intersection is (2, 8), then that must mean I graphed them correclly, right? @campbell_st

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1well you can always graph them as a valid method, rather than using the algebraic methods

Compassionate
 one year ago
Best ResponseYou've already chosen the best response.0Since we already graphed the first one, let me try the second one myself. 6x  4 = y So: y = 6x  4 My y intercept is 4 My x intercept is 0 = 6x  4 4 = 6x x = 4/6 or 0.67. I understand on a test you probably wouldn't be asked to graph 0.67, but for now this is just an example, but did I do the process right? These would, in theory, be my y and xintercepts.

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2well if i have to graph that equation i will draw a point at 4 and then use the fact slope = rise over run 6/1=rise over run for me this way is easier than the other one no need to solve for anything :=)

Compassionate
 one year ago
Best ResponseYou've already chosen the best response.0Ah, right, thank you. But If I was asked to find the xintercept, I would know how thanks to @campbell_st . Thank you @Nnesha . Wish I could medal you both

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2right good to have extra information! but i'm saying for graph good luck!
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