A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Compassionate

  • one year ago

Easiest way to graph an equation?

  • This Question is Closed
  1. Compassionate
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Say I have an equation in y = mx + b ... Lets ay, y = 2x + 4

  2. Compassionate
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    y-intercept = 4, so I would graph 4 on the y-axis Now, my slope is 2x, so I could just graph 2? Or would I have to plug in values for 2, like x = 1 x = 0 x = -1 or will just graphing 2 be enough?

  3. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    slope = rise over run and you can write 2 as 2/1 \[\huge\rm slope =\frac{ rise }{ run }\]

  4. campbell_st
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    And I thought the easiest way was to use technology can you graph y = x/(x^2 + 1) using this method

  5. Compassionate
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Right, so would I calculate my slope from my y-intercept.

  6. Compassionate
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Let's stick to linear equations @campbell_st , all those hyperboles and binomials don't sit well with me

  7. campbell_st
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    well I'd still say technology is the easiest method is if its only straight lines

  8. Compassionate
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    If only I could use graphing technology on standardized testing

  9. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    yes right first draw a point on y-axis (yintercept) and btw slope is just 2 x is a variable not slope |dw:1443991125916:dw|

  10. Compassionate
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1443991206348:dw|

  11. Compassionate
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so it would look something like this?

  12. campbell_st
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    don't forget you should choose 3 independent values.... to avoid errors

  13. campbell_st
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    but what if the line has no slope...

  14. Compassionate
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    X is independent, right? y = 2x + 4 y = 2(1) + 4 y = 6 y = 2(2) + 4 y = 8 y = 2(3) + 4 y = 10 Like that?

  15. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1443991283848:dw| looks good to me but to draw a perfect line you can go down down left one as wll

  16. Compassionate
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    If the line had no slope, say y = 4 Wouldn't I just graph a horizontal line across the y-axis, since it has no point of intersection on the x-axis? A line with no slope is either parallel to x when y = a number, or parallel to y when x = a number

  17. Compassionate
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1443991488766:dw|

  18. campbell_st
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    why not graph the line using intercepts.. y = 2x + 4 x- intercept -2 when y = 0 and y intercept 4 when x = 0 that's an easy method

  19. idku
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    y=mx+b 0=mx+b --> -b=mx --> -b/m=x point: (-b/m, 0) y=m(0)+b --> y=b point: (0,b) Graph the points (0, b) and (-b/m, 0) and connect them with a ruler.

  20. Compassionate
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    You guys are confusing me with al these different methods.

  21. idku
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    just extract two points (intercepts are easier to find), and connect the dots. This is all.

  22. Compassionate
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    y = 2x + 4 0 = 2x + 4 - 4 = 2x x = -2 Then y = 0 + 4 y = 4 So I can graph (-2, 0), (0, 4) Then that will give me bot the intercepts. I get it.

  23. idku
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    and connect intercepts (after you graph them) with a ruler.

  24. Compassionate
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    What if I'm given two equations to graph now. Say y = 2x + 4 6x - 3x = y And one of my equations isn't in y = mx + b, should I convert my second equation to y = mx + b or what?

  25. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    to graph an equation we dont' really need to find intercepts but you CAN if you want

  26. idku
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    well, you can use a graphing calculator, but it is not called you graphing it....

  27. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    yes first you have to rewrite the equation in slope intercept

  28. idku
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    the easiest I would do, when I have a y=mx+b to graph, 1) Find y and x intercepts 2) Graph these two points (the y and x intercepts you have found) 3) Connect the intercepts with a rule Bam!

  29. Compassionate
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    y = 2x + 4 6x - 3 = y Now, what if I solve it... Like y = 2x + 4 y = -6x + 4 Is that right?

  30. idku
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    you want to solve the system, right?

  31. Compassionate
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    WEll, I Want to graph it

  32. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    both equations are already in slope intercept form :D

  33. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    i guess there is a typo are you sure it's `6x-3x`=y ?

  34. idku
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    y = 2x + 4 6x - 4 = y multiply equation#2 times -1. y = 2x + 4 -6x + 4 = -y now we will do addition to eliminate the y. y = 2x + 4 -y = -6x + 4 ------------- 0 = -4x + 8

  35. idku
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I guess it was -4 in eq2?

  36. Compassionate
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    y = 2x + 4 6x - 4 = y Why not just 6x - 4 = 2x + 4 4x = 8 x = 2 y = 2(2) + 4 y = 4 + 4 y = 8 So, (2, 8) would be the point of intersection, right? That's where the two lines cross.

  37. idku
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    sure, good!

  38. idku
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I for some reason prefered elimination

  39. Compassionate
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    If I wanted to graph the lines, would I just put them both in y = mx+ b and just use the aforementioned method to just graph each line individually?

  40. campbell_st
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    perhaps you can graph them to check... that's easy

  41. Compassionate
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    If I graph them and my point of intersection is (2, 8), then that must mean I graphed them correclly, right? @campbell_st

  42. campbell_st
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    well you can always graph them as a valid method, rather than using the algebraic methods

  43. Compassionate
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Since we already graphed the first one, let me try the second one myself. 6x - 4 = y So: y = 6x - 4 My y intercept is -4 My x intercept is 0 = 6x - 4 4 = 6x x = 4/6 or 0.67. I understand on a test you probably wouldn't be asked to graph 0.67, but for now this is just an example, but did I do the process right? These would, in theory, be my y and x-intercepts.

  44. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    well if i have to graph that equation i will draw a point at -4 and then use the fact slope = rise over run 6/1=rise over run for me this way is easier than the other one no need to solve for anything :=)

  45. Compassionate
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Ah, right, thank you. But If I was asked to find the x-intercept, I would know how thanks to @campbell_st . Thank you @Nnesha . Wish I could medal you both

  46. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    right good to have extra information! but i'm saying for graph good luck!

  47. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.