anonymous
  • anonymous
There are 30 homes in Neighborhood A. Each year, the number of homes increases by 20%. Just down the road, Neighborhood B has 45 homes. Each year, 3 new homes are built in Neighborhood B. Part A: Write functions to represent the number of homes in Neighborhood A and Neighborhood B throughout the years. (4 points) Part B: How many homes does Neighborhood A have after 5 years? How many does Neighborhood B have after the same number of years? (2 points) Part C: After approximately how many years is the number of homes in Neighborhood A and Neighborhood B the same? Justify your answer mathema
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
A.\[no.~ of~ homes~after~n ~years=30(1+\frac{ 20 }{ 100 })^n\] for B \[a _{n}=a+\left( n-1 \right)d\] where a=45,d=3,n= no. of years
anonymous
  • anonymous
part B put n=5 in the above formulas compound formula above give total no. of homes for Neighborhood A second formula correction \[a _{n}=a+nd\] \[a _{5}=45+3*5=?\]
anonymous
  • anonymous
Part C \[30\left( 1.2 \right)^n=45+3n\] find n

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Can anyone please give me the answer?
anonymous
  • anonymous
To all three parts?
anonymous
  • anonymous
I've been stuck on the same question for like ever and I just want to get it over with!
anonymous
  • anonymous
Part C divide by 3 \[10(1.2)^n=15+n\] for n=1 10*1.2=15+1 12=16 for n=2 10*1.44=15+2 14.4=17 for n=3 \[10\left( 1.2 \right)^3=15+3,17.28=18\] for n=4 \[10\left( 1.2 \right)^4=15+4,20.73=19\] so approximately after 3 years,no. of houses is same.
anonymous
  • anonymous
part B after 5 years no. of houses in neighborhood A\[=30\left( 1.2 \right)^5=75.93=76 \approx.\] no. of houses in neighborhood B=45+3*5=45+15=60

Looking for something else?

Not the answer you are looking for? Search for more explanations.