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anonymous
 one year ago
There are 30 homes in Neighborhood A. Each year, the number of homes increases by 20%. Just down the road, Neighborhood B has 45 homes. Each year, 3 new homes are built in Neighborhood B.
Part A: Write functions to represent the number of homes in Neighborhood A and Neighborhood B throughout the years. (4 points)
Part B: How many homes does Neighborhood A have after 5 years? How many does Neighborhood B have after the same number of years? (2 points)
Part C: After approximately how many years is the number of homes in Neighborhood A and Neighborhood B the same? Justify your answer mathema
anonymous
 one year ago
There are 30 homes in Neighborhood A. Each year, the number of homes increases by 20%. Just down the road, Neighborhood B has 45 homes. Each year, 3 new homes are built in Neighborhood B. Part A: Write functions to represent the number of homes in Neighborhood A and Neighborhood B throughout the years. (4 points) Part B: How many homes does Neighborhood A have after 5 years? How many does Neighborhood B have after the same number of years? (2 points) Part C: After approximately how many years is the number of homes in Neighborhood A and Neighborhood B the same? Justify your answer mathema

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0A.\[no.~ of~ homes~after~n ~years=30(1+\frac{ 20 }{ 100 })^n\] for B \[a _{n}=a+\left( n1 \right)d\] where a=45,d=3,n= no. of years

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0part B put n=5 in the above formulas compound formula above give total no. of homes for Neighborhood A second formula correction \[a _{n}=a+nd\] \[a _{5}=45+3*5=?\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Part C \[30\left( 1.2 \right)^n=45+3n\] find n

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can anyone please give me the answer?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I've been stuck on the same question for like ever and I just want to get it over with!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Part C divide by 3 \[10(1.2)^n=15+n\] for n=1 10*1.2=15+1 12=16 for n=2 10*1.44=15+2 14.4=17 for n=3 \[10\left( 1.2 \right)^3=15+3,17.28=18\] for n=4 \[10\left( 1.2 \right)^4=15+4,20.73=19\] so approximately after 3 years,no. of houses is same.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0part B after 5 years no. of houses in neighborhood A\[=30\left( 1.2 \right)^5=75.93=76 \approx.\] no. of houses in neighborhood B=45+3*5=45+15=60
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