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sin13=5/c, 5*sin13, c=5*sin13
hmmm to find 3rd side you should know one angle and one side sin = opposite over hyp right ?
but the hypotenuse isn't known in this case
right i want u to take a few sec and think about is it sin 13 = 5 /c correct ? sin = opposite over hyp and we are looking at angle B which is 13
given is a which is 5
no it's not correct! :) I was looking at angle A
so we can use tan77=b/5
well sin B = opposite over hyp but the opposite of angle B isn't given
but we can find out what angle b is.. it's 77 degrees
|dw:1443995567775:dw| we don't konw what c equal to and we don't know what is B so you can't use sin for angle B
\[\angle A = 90^\circ - \angle B\]
yes that's correct tan 77 = b/5
no wait a sec looking at wrong angle
nvm that's correct tan B = b/5
so should i write 5tan(77)?
for the length of b
and for c we can do sin(13)=5/c
I got 5/sin13
the last one was incorrect :)
what which one ?? :o
for length of c
well 77+90 =167 subtract from 180 180-167 =13 |dw:1443996138575:dw| looks right
or maybe they want u to use given angle which si 77 to finfd length c
I ended up getting 5/cos(77)
did you put parentheses for 5/sin(13 ) ?
5/cos(77) was correct :) thank you lots!
hmm note for next time only use given angle
Got ya :) It's something I need to review!
yes right and t trust urself you're really good at math just need little review good lukc o^_^o