Exact measures

- anonymous

Exact measures

- schrodinger

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- anonymous

##### 1 Attachment

- anonymous

sin13=5/c, 5*sin13, c=5*sin13

- Nnesha

hmmm to find 3rd side you should know one angle and one side sin = opposite over hyp right ?

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## More answers

- anonymous

but the hypotenuse isn't known in this case

- Nnesha

right i want u to take a few sec and think about is it sin 13 = 5 /c correct ?
sin = opposite over hyp
and we are looking at angle B which is 13

- Nnesha

given is a which is 5

- anonymous

no it's not correct! :) I was looking at angle A

- anonymous

so we can use tan77=b/5

- Nnesha

well sin B = opposite over hyp but the opposite of angle B isn't given

- Nnesha

|dw:1443995559282:dw|

- anonymous

but we can find out what angle b is.. it's 77 degrees

- Nnesha

|dw:1443995567775:dw|
we don't konw what c equal to and we don't know what is B
so you can't use sin for angle B

- Jhannybean

\[\angle A = 90^\circ - \angle B\]

- Nnesha

yes that's correct tan 77 = b/5

- Nnesha

no wait a sec looking at wrong angle

- Nnesha

nvm that's correct tan B = b/5

- anonymous

so should i write 5tan(77)?

- anonymous

for the length of b

- Nnesha

looks good

- anonymous

and for c we can do sin(13)=5/c

- anonymous

I got 5/sin13

- Nnesha

\(\huge\color{green}{\checkmark}\)

- anonymous

the last one was incorrect :)

- Nnesha

what which one ?? :o

- anonymous

for length of c

- Nnesha

well 77+90 =167
subtract from 180
180-167 =13 |dw:1443996138575:dw|
looks right

- Nnesha

or maybe they want u to use given angle which si 77 to finfd length c

- anonymous

I ended up getting 5/cos(77)

- Nnesha

yes right

- Nnesha

did you put parentheses for 5/sin(13 ) ?

- anonymous

5/cos(77) was correct :) thank you lots!

- Nnesha

hmm note for next time only use given angle

- Nnesha

the*

- anonymous

Got ya :) It's something I need to review!

- Nnesha

yes right and t trust urself you're really good at math just need little review good lukc o^_^o

- Nnesha

luck**

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