## anonymous one year ago I need help with math questions can someone inbox me please

1. anonymous

It's a picture of math question how do I post it

2. zepdrix

@bella280 you can use the "attach file" button located at the bottom of the text box here! :)

3. anonymous

There's none :( I'm doing it from my cell phone. Do I need to get on a computer to attach a file?

4. zepdrix

oh... probably :c

5. anonymous

Okay I'm going to try right now

6. anonymous

7. anonymous

first file is numbers 10-21 second file is numbers 28-31 third file is numbers 24-39

8. zepdrix

Hold on, Im gonna repost the images :) It's really bugging me that they're rotated lol

9. anonymous

sorry about that. thank you so much

10. anonymous

i had to send them for my cell phone to the computer. so the pictures got rotated for some weird reason. sorry again about that

11. zepdrix

So these guys, ya? :d

12. anonymous

yes those are the questions would you be able to help me with them

13. anonymous

and wow ur amazing with fixing pictures.

14. zepdrix

$\large\rm 3y\sqrt{98}+15y \sqrt2$With this type of problem, they usually want you to try and get both roots in terms of the smaller one. So here, we'd like to write both as a $$\large\rm \sqrt2$$ if we are able to. I'll show you how we can do that with the 98,$\large\rm \sqrt{98}=\sqrt{49\cdot2}=\sqrt{49}\cdot\sqrt2=7\cdot2$What I'm doing is: I'm writing 98 as 49*2, then im writing them as separate roots, because the 49 can come out of the root.

15. zepdrix

Woops! typo on that last step :)

16. zepdrix

$\large\rm \color{orangered}{\sqrt{49}}\cdot\sqrt2=\color{orangered}{7}\cdot\sqrt{2}$

17. anonymous

would you actually be able to give me all the answers to the problems. because i just want to check my work. please

18. zepdrix

no sorry :c

19. anonymous

:( please i know im a stranger and all its just im so stressed out and im studying for a bug exam tomorrow. it would mean the world to me

20. zepdrix

I can show you how to do a few of them :O I'm not gonna do your homework for you though XD lol $\large\rm 3y\color{orangered}{\sqrt{98}}+15y \sqrt2$$\large\rm 3y\color{orangered}{\sqrt{49\cdot2}}+15y \sqrt2$$\large\rm 3y\color{orangered}{\sqrt{49}\cdot\sqrt{2}}+15y \sqrt2$$\large\rm 3y\color{orangered}{\cdot7\cdot\sqrt{2}}+15y \sqrt2$Multiply the 7 and 3,$\large\rm 21y \sqrt2+15y \sqrt2$Think of y sqrt(2) as your ..thing. $$\large\rm y\sqrt2=apple$$ So the problem is really just$\large\rm 21apples+15apples$So we get$\large\rm 36apples=36y \sqrt2$for our answer.

21. anonymous

okay can u do like 5 of them questions

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