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anonymous
 one year ago
I need help with math questions can someone inbox me please
anonymous
 one year ago
I need help with math questions can someone inbox me please

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It's a picture of math question how do I post it

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0@bella280 you can use the "attach file" button located at the bottom of the text box here! :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0There's none :( I'm doing it from my cell phone. Do I need to get on a computer to attach a file?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay I'm going to try right now

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0first file is numbers 1021 second file is numbers 2831 third file is numbers 2439

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0Hold on, Im gonna repost the images :) It's really bugging me that they're rotated lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry about that. thank you so much

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i had to send them for my cell phone to the computer. so the pictures got rotated for some weird reason. sorry again about that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes those are the questions would you be able to help me with them

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and wow ur amazing with fixing pictures.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0\[\large\rm 3y\sqrt{98}+15y \sqrt2\]With this type of problem, they usually want you to try and get both roots in terms of the smaller one. So here, we'd like to write both as a \(\large\rm \sqrt2\) if we are able to. I'll show you how we can do that with the 98,\[\large\rm \sqrt{98}=\sqrt{49\cdot2}=\sqrt{49}\cdot\sqrt2=7\cdot2\]What I'm doing is: I'm writing 98 as 49*2, then im writing them as separate roots, because the 49 can come out of the root.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0Woops! typo on that last step :)

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0\[\large\rm \color{orangered}{\sqrt{49}}\cdot\sqrt2=\color{orangered}{7}\cdot\sqrt{2}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0would you actually be able to give me all the answers to the problems. because i just want to check my work. please

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0:( please i know im a stranger and all its just im so stressed out and im studying for a bug exam tomorrow. it would mean the world to me

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0I can show you how to do a few of them :O I'm not gonna do your homework for you though XD lol \[\large\rm 3y\color{orangered}{\sqrt{98}}+15y \sqrt2\]\[\large\rm 3y\color{orangered}{\sqrt{49\cdot2}}+15y \sqrt2\]\[\large\rm 3y\color{orangered}{\sqrt{49}\cdot\sqrt{2}}+15y \sqrt2\]\[\large\rm 3y\color{orangered}{\cdot7\cdot\sqrt{2}}+15y \sqrt2\]Multiply the 7 and 3,\[\large\rm 21y \sqrt2+15y \sqrt2\]Think of y sqrt(2) as your ..thing. \(\large\rm y\sqrt2=apple\) So the problem is really just\[\large\rm 21apples+15apples\]So we get\[\large\rm 36apples=36y \sqrt2\]for our answer.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay can u do like 5 of them questions
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