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anonymous

  • one year ago

I need help with math questions can someone inbox me please

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  1. anonymous
    • one year ago
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    It's a picture of math question how do I post it

  2. zepdrix
    • one year ago
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    @bella280 you can use the "attach file" button located at the bottom of the text box here! :)

  3. anonymous
    • one year ago
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    There's none :( I'm doing it from my cell phone. Do I need to get on a computer to attach a file?

  4. zepdrix
    • one year ago
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    oh... probably :c

  5. anonymous
    • one year ago
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    Okay I'm going to try right now

  6. anonymous
    • one year ago
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  7. anonymous
    • one year ago
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    first file is numbers 10-21 second file is numbers 28-31 third file is numbers 24-39

  8. zepdrix
    • one year ago
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    Hold on, Im gonna repost the images :) It's really bugging me that they're rotated lol

  9. anonymous
    • one year ago
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    sorry about that. thank you so much

  10. anonymous
    • one year ago
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    i had to send them for my cell phone to the computer. so the pictures got rotated for some weird reason. sorry again about that

  11. zepdrix
    • one year ago
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    So these guys, ya? :d

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  12. anonymous
    • one year ago
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    yes those are the questions would you be able to help me with them

  13. anonymous
    • one year ago
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    and wow ur amazing with fixing pictures.

  14. zepdrix
    • one year ago
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    \[\large\rm 3y\sqrt{98}+15y \sqrt2\]With this type of problem, they usually want you to try and get both roots in terms of the smaller one. So here, we'd like to write both as a \(\large\rm \sqrt2\) if we are able to. I'll show you how we can do that with the 98,\[\large\rm \sqrt{98}=\sqrt{49\cdot2}=\sqrt{49}\cdot\sqrt2=7\cdot2\]What I'm doing is: I'm writing 98 as 49*2, then im writing them as separate roots, because the 49 can come out of the root.

  15. zepdrix
    • one year ago
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    Woops! typo on that last step :)

  16. zepdrix
    • one year ago
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    \[\large\rm \color{orangered}{\sqrt{49}}\cdot\sqrt2=\color{orangered}{7}\cdot\sqrt{2}\]

  17. anonymous
    • one year ago
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    would you actually be able to give me all the answers to the problems. because i just want to check my work. please

  18. zepdrix
    • one year ago
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    no sorry :c

  19. anonymous
    • one year ago
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    :( please i know im a stranger and all its just im so stressed out and im studying for a bug exam tomorrow. it would mean the world to me

  20. zepdrix
    • one year ago
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    I can show you how to do a few of them :O I'm not gonna do your homework for you though XD lol \[\large\rm 3y\color{orangered}{\sqrt{98}}+15y \sqrt2\]\[\large\rm 3y\color{orangered}{\sqrt{49\cdot2}}+15y \sqrt2\]\[\large\rm 3y\color{orangered}{\sqrt{49}\cdot\sqrt{2}}+15y \sqrt2\]\[\large\rm 3y\color{orangered}{\cdot7\cdot\sqrt{2}}+15y \sqrt2\]Multiply the 7 and 3,\[\large\rm 21y \sqrt2+15y \sqrt2\]Think of y sqrt(2) as your ..thing. \(\large\rm y\sqrt2=apple\) So the problem is really just\[\large\rm 21apples+15apples\]So we get\[\large\rm 36apples=36y \sqrt2\]for our answer.

  21. anonymous
    • one year ago
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    okay can u do like 5 of them questions

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