marihelenh one year ago The gold foil used by Ernst Rutherford in his investigations 1 um thick. Given that the radius of gold is approximately 130 pm, how many atoms thick was the foil?

1. aaronq

How many atoms fit across the foil (assuming they're liked up side by side) $$1~\mu m=1.0*10^{6}~pm$$

2. marihelenh

$\frac{ 130p m }{ 1 } * \frac{ 1\mu m }{ 1.0*10^{6}p m }$

3. marihelenh

Is this how I would set that part up?

4. marihelenh

@aaronq

5. aaronq

yes that would give you the size of one atom in micrometers, then you divide 1 micrometer (the thickness of the foil) by the size of 1 atom (in micrometers)