marihelenh
  • marihelenh
The gold foil used by Ernst Rutherford in his investigations 1 um thick. Given that the radius of gold is approximately 130 pm, how many atoms thick was the foil?
Chemistry
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
aaronq
  • aaronq
How many atoms fit across the foil (assuming they're liked up side by side) \(1~\mu m=1.0*10^{6}~pm\)
marihelenh
  • marihelenh
\[\frac{ 130p m }{ 1 } * \frac{ 1\mu m }{ 1.0*10^{6}p m }\]
marihelenh
  • marihelenh
Is this how I would set that part up?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

marihelenh
  • marihelenh
@aaronq
aaronq
  • aaronq
yes that would give you the size of one atom in micrometers, then you divide 1 micrometer (the thickness of the foil) by the size of 1 atom (in micrometers)

Looking for something else?

Not the answer you are looking for? Search for more explanations.