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cooltowl
 one year ago
With 4.95 g of baking soda, how many moles of NaOH should be formed?
Using stoichiometric calculations
Reaction 1: 1 NaHCO3(s) → 1 NaOH(s) + 1 CO2(g)
cooltowl
 one year ago
With 4.95 g of baking soda, how many moles of NaOH should be formed? Using stoichiometric calculations Reaction 1: 1 NaHCO3(s) → 1 NaOH(s) + 1 CO2(g)

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aaronq
 one year ago
Best ResponseYou've already chosen the best response.11. Convert the mass to moles 2. write a ratio of the chemical compounds of interest and their respective stoichiometric coefficients \(\sf \dfrac{moles~of~baking~soda}{baking~soda's~coefficient}=\dfrac{moles~of~NaOH}{NaOH's~coefficient}\) 3. solve for moles of NaOH use \(\sf moles=\dfrac{mass}{molar~mass}\) for 1. and 3.

cooltowl
 one year ago
Best ResponseYou've already chosen the best response.0would it look like this, .0589/1=.123759/1

aaronq
 one year ago
Best ResponseYou've already chosen the best response.1yes it would. for this example the ratio doesn't really matter because both coefficients are equal to 1, but this is how you solve all stoichiometry problems.

aaronq
 one year ago
Best ResponseYou've already chosen the best response.1wait, no, where did you get 0.123579?

aaronq
 one year ago
Best ResponseYou've already chosen the best response.1moles of NaOH should be your unknown variable in the ratio, what you are solving for.

cooltowl
 one year ago
Best ResponseYou've already chosen the best response.0.0589/1=?/1 .0589=?/1 How do I solve this because I keep on getting the wrong answer which is .0589

aaronq
 one year ago
Best ResponseYou've already chosen the best response.1it should be that, 0.058923 moles
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