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cooltowl

  • one year ago

With 4.95 g of baking soda, how many moles of NaOH should be formed? Using stoichiometric calculations Reaction 1: 1 NaHCO3(s) → 1 NaOH(s) + 1 CO2(g)

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  1. aaronq
    • one year ago
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    1. Convert the mass to moles 2. write a ratio of the chemical compounds of interest and their respective stoichiometric coefficients \(\sf \dfrac{moles~of~baking~soda}{baking~soda's~coefficient}=\dfrac{moles~of~NaOH}{NaOH's~coefficient}\) 3. solve for moles of NaOH use \(\sf moles=\dfrac{mass}{molar~mass}\) for 1. and 3.

  2. cooltowl
    • one year ago
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    would it look like this, .0589/1=.123759/1

  3. aaronq
    • one year ago
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    yes it would. for this example the ratio doesn't really matter because both coefficients are equal to 1, but this is how you solve all stoichiometry problems.

  4. aaronq
    • one year ago
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    wait, no, where did you get 0.123579?

  5. aaronq
    • one year ago
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    moles of NaOH should be your unknown variable in the ratio, what you are solving for.

  6. cooltowl
    • one year ago
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    .0589/1=?/1 .0589=?/1 How do I solve this because I keep on getting the wrong answer which is .0589

  7. aaronq
    • one year ago
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    it should be that, 0.058923 moles

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