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anonymous
 one year ago
Medal award! Suppose you start at the point (1,0) on a unit circle and move a distance t = 4.5 along the circle. What is the reference number for t?
Give an exact answer. Your answer may have pi in it! Please PREVIEW!
The reference number for 4.5 is t⎯
anonymous
 one year ago
Medal award! Suppose you start at the point (1,0) on a unit circle and move a distance t = 4.5 along the circle. What is the reference number for t? Give an exact answer. Your answer may have pi in it! Please PREVIEW! The reference number for 4.5 is t⎯

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i have no idea what a "reference number" is , do you know?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i have a guess, my guess is \(2\pi4.5\) but that is really just a guess

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it's the same as a reference angle

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh, that kind of begs the question is a "reference angle" between \(0\) and\(\frac{\pi}{2}\)?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Hmm ya the wording is a little strange here :d So we're starting at pi/2, ya? We're spinning 4.5 around,\[\large\rm \frac{\pi}{2}+4.5\]The way we get back to the reference angle depends on which quadrant we lie in. Turns out we're in quadrant 4, so to get our reference angle we would do \(\large\rm 2\pi\theta\) So I guess we haveeeeee\[\large\rm 2\pi\left(\frac{\pi}{2}+4.5\right)\]That seems kinda complicated though >.< Maybe that's not what they wanted hmm

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0zepdrix no I put that in it was incorrect :/

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Oh I'm so silly. We're starting at (1,0), not at (0,1)... So we're starting at an angle of 0, not pi/2.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Spinning to 4.5 puts us at \(\large\rm 0+4.5\) which is in quadrant 3. So to get back to our reference angle we would do \(\large\rm 4.5\pi\).

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thanks so much :) may I ask how you got 4.5?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1dw:1444007447856:dwHere is a handy chart showing you how to get your reference angle from each quadrant.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1dw:1444007656117:dwSo we started here at (1,0).

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1dw:1444007714494:dwIf we pi radians around the circle, we'd be going approximately 3.14 around.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1dw:1444007764708:dwBut they told us to go 4.5 around. So we have to go further. To figure out which quadrant you should be in, you need the decimal value for 3pi/2.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.13pi/2 ends up being approximately 4.7 4.5 is smaller than that value, so we're in quadrant 3! :)

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1And if you look back at my original chart, it shows you how to get from quad 3 to reference angle.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok :) thanks so much.. it's actually 3.5 not 4.5 though

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1what? 0_o it says 4.5 twice in the problem though lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have one that I was working on that's exactly the same for practice :) Thanks so much
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