Fanduekisses
  • Fanduekisses
pls help. ;'( use the properties of logarithms to rewrite and simplify the logarithmic expression.
Mathematics
schrodinger
  • schrodinger
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Fanduekisses
  • Fanduekisses
\[\log _{5}(\frac{ 1 }{ 250 })\]
Fanduekisses
  • Fanduekisses
\[\log_{5}(1)-\log_{5}(250)\]???
Fanduekisses
  • Fanduekisses

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Fanduekisses
  • Fanduekisses
then what?
amistre64
  • amistre64
the question seems vague. what constitutes a 'simplified' version of it?
amistre64
  • amistre64
what does log(1) always equal?
amistre64
  • amistre64
so 250 a multiple of 5 by chance?
amistre64
  • amistre64
what log properties do you know?
Fanduekisses
  • Fanduekisses
yes , 50 right
Fanduekisses
  • Fanduekisses
ohh could I use the change of base ? lol
Mertsj
  • Mertsj
log(base5) of1 = 0 so the simplified version is - log(base5)250
Fanduekisses
  • Fanduekisses
The answer key says it's -3-log(base 5) (2) but how?
amistre64
  • amistre64
notifs didnt say nothing about 15 minutes ago ...
amistre64
  • amistre64
what are your log properties?
Fanduekisses
  • Fanduekisses
Power, product, and quotient
Mertsj
  • Mertsj
Or perhaps this: \[\log_{5}1-\log_{5}5^3(2)=0-(\log_{5}5^3 +\log_{5}2)=-3-\log_{5}2 \]
Fanduekisses
  • Fanduekisses
omg, that makes so much sense, I see what was done there. :D
Fanduekisses
  • Fanduekisses
Pretty much all the log properties were used there haha. :)

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