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Fanduekisses

  • one year ago

pls help. ;'( use the properties of logarithms to rewrite and simplify the logarithmic expression.

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  1. Fanduekisses
    • one year ago
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    \[\log _{5}(\frac{ 1 }{ 250 })\]

  2. Fanduekisses
    • one year ago
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    \[\log_{5}(1)-\log_{5}(250)\]???

  3. Fanduekisses
    • one year ago
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    @amistre64 @dan815 @satellite73

  4. Fanduekisses
    • one year ago
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    then what?

  5. amistre64
    • one year ago
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    the question seems vague. what constitutes a 'simplified' version of it?

  6. amistre64
    • one year ago
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    what does log(1) always equal?

  7. amistre64
    • one year ago
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    so 250 a multiple of 5 by chance?

  8. amistre64
    • one year ago
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    what log properties do you know?

  9. Fanduekisses
    • one year ago
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    yes , 50 right

  10. Fanduekisses
    • one year ago
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    ohh could I use the change of base ? lol

  11. Mertsj
    • one year ago
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    log(base5) of1 = 0 so the simplified version is - log(base5)250

  12. Fanduekisses
    • one year ago
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    The answer key says it's -3-log(base 5) (2) but how?

  13. amistre64
    • one year ago
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    notifs didnt say nothing about 15 minutes ago ...

  14. amistre64
    • one year ago
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    what are your log properties?

  15. Fanduekisses
    • one year ago
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    Power, product, and quotient

  16. Mertsj
    • one year ago
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    Or perhaps this: \[\log_{5}1-\log_{5}5^3(2)=0-(\log_{5}5^3 +\log_{5}2)=-3-\log_{5}2 \]

  17. Fanduekisses
    • one year ago
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    omg, that makes so much sense, I see what was done there. :D

  18. Fanduekisses
    • one year ago
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    Pretty much all the log properties were used there haha. :)

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