Equations problem

- blake57roger

Equations problem

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- blake57roger

##### 1 Attachment

- blake57roger

@Loser66

- blake57roger

@amistre64

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## More answers

- blake57roger

@freckles

- blake57roger

@dan815

- explicitvogue

-15-X=-6
You have to isolate X from the other numbers.
So first, add X to both sides.
You will be left with -15=-6+X
Now bring 6 to the other side by canceling it out.
You will be left with -15-6=X
Combine like terms.
-9=X or X=-9
Let me know if you need more help!

- blake57roger

cool i just got 9 to

- blake57roger

|dw:1444008829821:dw|

- blake57roger

@explicitvogue

- blake57roger

wait wouldnt it be 4

- explicitvogue

Again, to find X, you have to isolate and simplify! This time you would divide both sides by 4 since it's 4x. So tell me what you get

- explicitvogue

The answer wouldn't be 4, but you would divide both sides by 4.

- blake57roger

1 -9

- explicitvogue

4 times what will give you -36?

- explicitvogue

yes, -9! Good job!

- blake57roger

|dw:1444009073134:dw|

- explicitvogue

This is kind of like the first one. First, get the 4x by itself on one side of the = sign. How would you do that?

- blake57roger

6 is it 6

- blake57roger

no

- blake57roger

dont answer that

- blake57roger

36

- explicitvogue

No it's not 6. Do it step by step. If you add 9 to both sides, you will have 4x=36 which is exactly like the second problem.

- explicitvogue

right so 4x=36, now simplify that. X=?

- blake57roger

36

- explicitvogue

Nope 4x=36. you have to divide both sides by 4. so what is 4x/4? and after that, what is 36/4?

- blake57roger

if im wrong its because i hate these types of problems im always wrong some how just saying

- blake57roger

9

- explicitvogue

Coreect! x=9

- blake57roger

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- blake57roger

there

- blake57roger

ok if you do that im gonna take off the human calculator

- explicitvogue

Okay this one is a bit more difficult.
The first step is to distribute 6 into (-3-x). Do you know how to do that?

- explicitvogue

I can explain it if not.

- blake57roger

no kinda

- blake57roger

im not the best with these problems

- explicitvogue

It's okay, you are learning! Okay so 6(-3-x) basically means 6*-3 and 6*-x
So try that, and see what you get.
6*-3=_____
6*-x=_____

- blake57roger

6*3= -18

- explicitvogue

Right. and 6*-x?

- blake57roger

x

- explicitvogue

Nope, you are multiplying -x with 6.

- blake57roger

ok -x*6 you cant do can you

- blake57roger

x isnt a number

- explicitvogue

yes, you can! -x*6 is -6x

- blake57roger

oh

- explicitvogue

you can still multiply the two numbers, it would just make a consonant instead of an integer.

- blake57roger

ok

- explicitvogue

okay so now you have
-18-6x-2x=14
The next step is to combine the like terms. Can you do that?

- blake57roger

i can try so add them right

- blake57roger

8x

- explicitvogue

Well in this problem you would be subtracting not adding, but you have the right idea.

- explicitvogue

So what would be the whole problem now after you've done that?

- blake57roger

-18-8x

- explicitvogue

right! so -18-8x=14
Now you have to do what you did with the problems before, you have to get the number with the x on one side of the = by itself. Can you try that?

- blake57roger

yea

- explicitvogue

Okay, tell me what you get once you've tried

- blake57roger

-24x

- blake57roger

no

- blake57roger

would you add 8 to each side

- blake57roger

im in 8th grade and this still confuses me like why

- blake57roger

Like i should no this

- explicitvogue

Nope not quite. It would actually be easier to add 18 to each side. And it's okay! I'm a Junior in high school, and I didn't completely understand these kinds of problems until the end of 8th grade

- blake57roger

well i dont feel bad any more

- explicitvogue

so -18+18 would cancel out.
so you would have 8x=32. Now try to simplify that.

- explicitvogue

Never feel bad about thing you don't understand! Everyone learns at a different pace, and some things will come easier to you than others.

- blake57roger

4

- explicitvogue

Right!

- explicitvogue

See you're getting the hang of it!

- blake57roger

4=x

- explicitvogue

Yes! Good job!

- blake57roger

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- blake57roger

ok there

- blake57roger

do you know this

- blake57roger

would the anwser be 5

- blake57roger

x=5

- blake57roger

@explicitvogue

- blake57roger

@explicitvogue

- blake57roger

Bro @explicitvogue

- ganeshie8

\(x=5\) is correct

- blake57roger

ok

- blake57roger

##### 1 Attachment

- blake57roger

i have 3 more

- blake57roger

after this

- blake57roger

then im done

- ganeshie8

|dw:1444011952447:dw|

- ganeshie8

any ideas on how to start this problem ?

- blake57roger

kinda

- blake57roger

|dw:1444012161598:dw|

- ganeshie8

That's a very good start! so, you have :
\[\LARGE -\dfrac{1}{7}x+6=18\]
what would be the next step ?

- blake57roger

add -1/7x +6

- ganeshie8

Nope. you cannot combine them because they are not "like terms"
you cannot add coconuts and oranges

- ganeshie8

\[\LARGE -\dfrac{1}{7}x+6=18\]
your goal here is to isolate \(x\),
maybe subtract \(6\) both sides so that the left hand side looks simpler

- blake57roger

so i got -6/1/7 and 12

- blake57roger

!@ganeshie8

- blake57roger

@ganeshie8

- blake57roger

@pooja195

- blake57roger

@Directrix

- blake57roger

@Loser66

- blake57roger

@ganeshie8

- ganeshie8

Good,
\[\LARGE -\dfrac{1}{7}x+6=18\]
subtract \(6\) both sides and get
\[\LARGE -\dfrac{1}{7}x=12\]

- ganeshie8

\(x\) is still not isolated, what can be done to make it all by itself ?

- blake57roger

so x = 12

- blake57roger

i dont know

- ganeshie8

How can the equation \(-\dfrac{1}{7}x=12\) become the equation \(x=12\) ?

- ganeshie8

we need to follow some rules when isolating \(x\).
recall that we're allowed to multiply same number to both sides of an equation, so try multiplying \(-7\) both sides

- ganeshie8

Good,
\[\LARGE -\dfrac{1}{7}x+6=18\]
subtract \(6\) both sides and get
\[\LARGE -\dfrac{1}{7}x=12\]
multiply \(-7\) both sides and get
\[\LARGE x = -84\]

- ganeshie8

see if that makes sense..

- blake57roger

yes it does

- blake57roger

i haveone more then im done

- blake57roger

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- blake57roger

there

- ganeshie8

Suppose she has bought \(\large s\) small pots
it is given that each small pot costs \(\$2.4\)

- ganeshie8

so, how much she needs to pay for \(s\) small pots ?

- blake57roger

14-s

- ganeshie8

Nope, try again

- blake57roger

14+s

- blake57roger

@ganeshie8

- blake57roger

bro this is my last question

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