blake57roger
  • blake57roger
Equations problem
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
blake57roger
  • blake57roger
1 Attachment
blake57roger
  • blake57roger
@Loser66
blake57roger
  • blake57roger
@amistre64

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blake57roger
  • blake57roger
@freckles
blake57roger
  • blake57roger
@dan815
explicitvogue
  • explicitvogue
-15-X=-6 You have to isolate X from the other numbers. So first, add X to both sides. You will be left with -15=-6+X Now bring 6 to the other side by canceling it out. You will be left with -15-6=X Combine like terms. -9=X or X=-9 Let me know if you need more help!
blake57roger
  • blake57roger
cool i just got 9 to
blake57roger
  • blake57roger
|dw:1444008829821:dw|
blake57roger
  • blake57roger
@explicitvogue
blake57roger
  • blake57roger
wait wouldnt it be 4
explicitvogue
  • explicitvogue
Again, to find X, you have to isolate and simplify! This time you would divide both sides by 4 since it's 4x. So tell me what you get
explicitvogue
  • explicitvogue
The answer wouldn't be 4, but you would divide both sides by 4.
blake57roger
  • blake57roger
1 -9
explicitvogue
  • explicitvogue
4 times what will give you -36?
explicitvogue
  • explicitvogue
yes, -9! Good job!
blake57roger
  • blake57roger
|dw:1444009073134:dw|
explicitvogue
  • explicitvogue
This is kind of like the first one. First, get the 4x by itself on one side of the = sign. How would you do that?
blake57roger
  • blake57roger
6 is it 6
blake57roger
  • blake57roger
no
blake57roger
  • blake57roger
dont answer that
blake57roger
  • blake57roger
36
explicitvogue
  • explicitvogue
No it's not 6. Do it step by step. If you add 9 to both sides, you will have 4x=36 which is exactly like the second problem.
explicitvogue
  • explicitvogue
right so 4x=36, now simplify that. X=?
blake57roger
  • blake57roger
36
explicitvogue
  • explicitvogue
Nope 4x=36. you have to divide both sides by 4. so what is 4x/4? and after that, what is 36/4?
blake57roger
  • blake57roger
if im wrong its because i hate these types of problems im always wrong some how just saying
blake57roger
  • blake57roger
9
explicitvogue
  • explicitvogue
Coreect! x=9
blake57roger
  • blake57roger
1 Attachment
blake57roger
  • blake57roger
there
blake57roger
  • blake57roger
ok if you do that im gonna take off the human calculator
explicitvogue
  • explicitvogue
Okay this one is a bit more difficult. The first step is to distribute 6 into (-3-x). Do you know how to do that?
explicitvogue
  • explicitvogue
I can explain it if not.
blake57roger
  • blake57roger
no kinda
blake57roger
  • blake57roger
im not the best with these problems
explicitvogue
  • explicitvogue
It's okay, you are learning! Okay so 6(-3-x) basically means 6*-3 and 6*-x So try that, and see what you get. 6*-3=_____ 6*-x=_____
blake57roger
  • blake57roger
6*3= -18
explicitvogue
  • explicitvogue
Right. and 6*-x?
blake57roger
  • blake57roger
x
explicitvogue
  • explicitvogue
Nope, you are multiplying -x with 6.
blake57roger
  • blake57roger
ok -x*6 you cant do can you
blake57roger
  • blake57roger
x isnt a number
explicitvogue
  • explicitvogue
yes, you can! -x*6 is -6x
blake57roger
  • blake57roger
oh
explicitvogue
  • explicitvogue
you can still multiply the two numbers, it would just make a consonant instead of an integer.
blake57roger
  • blake57roger
ok
explicitvogue
  • explicitvogue
okay so now you have -18-6x-2x=14 The next step is to combine the like terms. Can you do that?
blake57roger
  • blake57roger
i can try so add them right
blake57roger
  • blake57roger
8x
explicitvogue
  • explicitvogue
Well in this problem you would be subtracting not adding, but you have the right idea.
explicitvogue
  • explicitvogue
So what would be the whole problem now after you've done that?
blake57roger
  • blake57roger
-18-8x
explicitvogue
  • explicitvogue
right! so -18-8x=14 Now you have to do what you did with the problems before, you have to get the number with the x on one side of the = by itself. Can you try that?
blake57roger
  • blake57roger
yea
explicitvogue
  • explicitvogue
Okay, tell me what you get once you've tried
blake57roger
  • blake57roger
-24x
blake57roger
  • blake57roger
no
blake57roger
  • blake57roger
would you add 8 to each side
blake57roger
  • blake57roger
im in 8th grade and this still confuses me like why
blake57roger
  • blake57roger
Like i should no this
explicitvogue
  • explicitvogue
Nope not quite. It would actually be easier to add 18 to each side. And it's okay! I'm a Junior in high school, and I didn't completely understand these kinds of problems until the end of 8th grade
blake57roger
  • blake57roger
well i dont feel bad any more
explicitvogue
  • explicitvogue
so -18+18 would cancel out. so you would have 8x=32. Now try to simplify that.
explicitvogue
  • explicitvogue
Never feel bad about thing you don't understand! Everyone learns at a different pace, and some things will come easier to you than others.
blake57roger
  • blake57roger
4
explicitvogue
  • explicitvogue
Right!
explicitvogue
  • explicitvogue
See you're getting the hang of it!
blake57roger
  • blake57roger
4=x
explicitvogue
  • explicitvogue
Yes! Good job!
blake57roger
  • blake57roger
1 Attachment
blake57roger
  • blake57roger
ok there
blake57roger
  • blake57roger
do you know this
blake57roger
  • blake57roger
would the anwser be 5
blake57roger
  • blake57roger
x=5
blake57roger
  • blake57roger
@explicitvogue
blake57roger
  • blake57roger
@explicitvogue
blake57roger
  • blake57roger
Bro @explicitvogue
ganeshie8
  • ganeshie8
\(x=5\) is correct
blake57roger
  • blake57roger
ok
blake57roger
  • blake57roger
1 Attachment
blake57roger
  • blake57roger
i have 3 more
blake57roger
  • blake57roger
after this
blake57roger
  • blake57roger
then im done
ganeshie8
  • ganeshie8
|dw:1444011952447:dw|
ganeshie8
  • ganeshie8
any ideas on how to start this problem ?
blake57roger
  • blake57roger
kinda
blake57roger
  • blake57roger
|dw:1444012161598:dw|
ganeshie8
  • ganeshie8
That's a very good start! so, you have : \[\LARGE -\dfrac{1}{7}x+6=18\] what would be the next step ?
blake57roger
  • blake57roger
add -1/7x +6
ganeshie8
  • ganeshie8
Nope. you cannot combine them because they are not "like terms" you cannot add coconuts and oranges
ganeshie8
  • ganeshie8
\[\LARGE -\dfrac{1}{7}x+6=18\] your goal here is to isolate \(x\), maybe subtract \(6\) both sides so that the left hand side looks simpler
blake57roger
  • blake57roger
so i got -6/1/7 and 12
blake57roger
  • blake57roger
!@ganeshie8
blake57roger
  • blake57roger
@ganeshie8
blake57roger
  • blake57roger
@pooja195
blake57roger
  • blake57roger
@Directrix
blake57roger
  • blake57roger
@Loser66
blake57roger
  • blake57roger
@ganeshie8
ganeshie8
  • ganeshie8
Good, \[\LARGE -\dfrac{1}{7}x+6=18\] subtract \(6\) both sides and get \[\LARGE -\dfrac{1}{7}x=12\]
ganeshie8
  • ganeshie8
\(x\) is still not isolated, what can be done to make it all by itself ?
blake57roger
  • blake57roger
so x = 12
blake57roger
  • blake57roger
i dont know
ganeshie8
  • ganeshie8
How can the equation \(-\dfrac{1}{7}x=12\) become the equation \(x=12\) ?
ganeshie8
  • ganeshie8
we need to follow some rules when isolating \(x\). recall that we're allowed to multiply same number to both sides of an equation, so try multiplying \(-7\) both sides
ganeshie8
  • ganeshie8
Good, \[\LARGE -\dfrac{1}{7}x+6=18\] subtract \(6\) both sides and get \[\LARGE -\dfrac{1}{7}x=12\] multiply \(-7\) both sides and get \[\LARGE x = -84\]
ganeshie8
  • ganeshie8
see if that makes sense..
blake57roger
  • blake57roger
yes it does
blake57roger
  • blake57roger
i haveone more then im done
blake57roger
  • blake57roger
1 Attachment
blake57roger
  • blake57roger
there
ganeshie8
  • ganeshie8
Suppose she has bought \(\large s\) small pots it is given that each small pot costs \(\$2.4\)
ganeshie8
  • ganeshie8
so, how much she needs to pay for \(s\) small pots ?
blake57roger
  • blake57roger
14-s
ganeshie8
  • ganeshie8
Nope, try again
blake57roger
  • blake57roger
14+s
blake57roger
  • blake57roger
@ganeshie8
blake57roger
  • blake57roger
bro this is my last question

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