## anonymous one year ago medal award!

1. anonymous

2. zepdrix

Make sure you remember how to read these brackets. Square bracket means we include the point, round bracket is exclusion.$\large\rm t\in[0,2\pi)\qquad\to\qquad 0\le t\lt 2\pi$

3. zepdrix

t=2pi isn't in our interval, ya?

4. anonymous

it is totally in our interval :D

5. zepdrix

Nooo :O

6. zepdrix

Round bracket on the 2pi

7. anonymous

Darn! I keep forgetting. It would be like this (2pi)

8. zepdrix

$\huge\rm t\in[0,2\pi\color{red}{)}\qquad\to\qquad 0\le t\color{red}{\lt} 2\pi$No 2pi allowed :OOO

9. anonymous

so whenever they are asking the distance what exactly do they want?

10. zepdrix

Well... you're right. If we spun 2pi, we'd get to the point they labeled. So we need a value that is co-terminal with 2pi and inside our interval.

11. zepdrix

If we spin around 2pi, we get to 4pi. That's way way outside of our interval though. Can we go backwards and get to a value in our interval maybe?

12. anonymous

Don't know if this is right but maybe pi/2?

13. zepdrix

No. You need to spin a full rotation to find co-terminal angles. full rotation = 2pi, ya?

14. zepdrix

So if we're at 2pi, and we spin backwards an entire rotation, where do we land?

15. anonymous

-2pi?

16. zepdrix

Hmm that certainly is co-terminal with 2pi :) But from 2pi, you spun around the circle TWICE to get to -2pi. Too far. That's outside of our interval.

17. zepdrix

You're gonna be so mad when you figure out how simple this was LOL

18. anonymous

pi/6?

19. zepdrix

pi/6 is not co-terminal to 2pi :c Should I just spill the beans? :3

20. anonymous

yes :D I honestly don't know what it is

21. zepdrix

We're starting at (1,0) and ending at (1,0). In order for this to happen, we have to spin multiples of 2pi. If we're between 0 and 2pi (excluding the value 2pi), then we have to spin how many 2pi's around to land in the same spot? 0 of them. t=0

22. anonymous

o wow. XD

23. anonymous

it's really that simple :)

24. zepdrix

Ya, kind of a trick question :c The point to point tells us that we have to move 2pi's. But the interval tells us that we're not able to. So you can't move at all :p

25. anonymous

thank you zepdrix :)