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anonymous
 one year ago
determine the polynomial function whose graph passes through the given points (1,1) (0,0) (1,1) (2,4)
anonymous
 one year ago
determine the polynomial function whose graph passes through the given points (1,1) (0,0) (1,1) (2,4)

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amistre64
 one year ago
Best ResponseYou've already chosen the best response.1we have 4 reference points, what do you consider we can do with them?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.14 equations, with 4 unknowns ... can we do matrix stuff yet?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1thats only 3 unknowns :) lets go another degree

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oooohhhh ax^3 +bx^2+cx

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1ax^3 + bx^2 + cx + d = y

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1but yeah, since 0,0, then d=0 by default

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so then dw:1444009179944:dw

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1the 0 0 0 0 is not required, but yeah, its fine. then row reduce it to echelon form rref{{(1)^3,(1)^2,(1)^1,(1)},{(1)^3,(1)^2,(1)^1,(1)},{(2)^3,(2)^2,(2)^1,(4)}}

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1for checking .. if the link posts properly http://www.wolframalpha.com/input/?i=rref {{%281%29^3%2C%281%29^2%2C%281%29^1%2C%281%29}%2C{%281%29^3%2C%281%29^2%2C%281%29^1%2C%281%29}%2C{%282%29^3%2C%282%29^2%2C%282%29^1%2C%284%29}}

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so my matrix table is right then

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1only thing that may be off is that you dont have your column for d, but d=0 due to the point 0,0

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1dw:1444009601928:dw

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1your last column is a y column .. you had no d variable column

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1dw:1444009738187:dw

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1dw:1444009782699:dw

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1each column is an unknown, and the last is the y ... we have 4 unknown so we need 4 columns, and a 5th one for y

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1IF we can already determine a variable, then it is reduced to 3 unknown ... 3 columns and a 4th for y

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1ax^3 + bx^2 + cx + d = y 1a + 1b + 1c + 1d = 1 0a + 0b + 0c + 1d = 0 1a + 1b + 1c + 1d = 1 8a + 4b + 2c + 1d = 1

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1do you see that d=0 already? if not we can simply work the matrix with these columns as is

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0alright thanks ill go ahead and work on it now

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so now how do i graph it
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