anonymous
  • anonymous
medal award!
Mathematics
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anonymous
  • anonymous
medal award!
Mathematics
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
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anonymous
  • anonymous
Mertsj
  • Mertsj
|dw:1444010001441:dw|
Mertsj
  • Mertsj
|dw:1444010141884:dw|

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anonymous
  • anonymous
I don't really understand what is what..
Mertsj
  • Mertsj
It's learning the unit circle I think with emphasis on the angles of the special right triangles.
anonymous
  • anonymous
if i'm not mistaken the two distances than are 5pi/4 and pi/4?
Mertsj
  • Mertsj
\[\sin \frac{\pi}{4}=\cos \frac{\pi}{4}=\frac{\sqrt{2}}{2}\]
Mertsj
  • Mertsj
So whenever you have a reference angle of pi/4, the sin and cos will be sqrt2/2 making adjustment for the sign depending on the quadrant.
Mertsj
  • Mertsj
So if the cos, which is like x, is -sqrt2/2, you must be in either quadrant 2 or 3 and the reference angle must be pi/4
Mertsj
  • Mertsj
And so the distance on the unit circle would be pi-pi/4 and pi + pi/4 or 3pi/4 and 5pi/4
anonymous
  • anonymous
but speficially for this problem when it refers to the distances they just want (sqrt(2)/2,sqrt(2)/2)?
Mertsj
  • Mertsj
No. They want the distance traveled on the unit circle.
Mertsj
  • Mertsj
Or in other words, they want the angle
anonymous
  • anonymous
I put in 5pi/4 and 3pi/4 it said it's incorrect
Mertsj
  • Mertsj
Well then it must be a formatting problem because if the x value is -sqrt2/2, the angles are 3pi/4 and 5pi/4
Mertsj
  • Mertsj
did you put in the comma?
anonymous
  • anonymous
i put in 3pi/4, 5pi/4
anonymous
  • anonymous
it's right! I probably forgot to add in the comma the first time :) thank you
Mertsj
  • Mertsj
yw

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