anonymous
  • anonymous
If the following elements were to form ions, they would attain the same number of electrons as which noble gas? elements: Be, Ca, Al, Rb, Se, F, P noble gas: He, Ne, Ar, Kr
Chemistry
chestercat
  • chestercat
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Photon336
  • Photon336
You need to first identify what group those elements are in first Beryllium and calcium are both in group 2. they are metals so they are going to lose 2 electrons. Calcium has 20 electrons and 20 protons, if it loses 2 electrons it's configuration resembles Argon. Beryllium has 4 protons and 4 electrons. if it loses 2 electrons it has 2 electrons now and this configuration resembles helium.
Photon336
  • Photon336
Photon336
  • Photon336
Try fluorine and tell me what noble gas it would represent

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anonymous
  • anonymous
Fluorine has 9 protons and 9 electrons?
Photon336
  • Photon336
yes
Photon336
  • Photon336
does it want to gain electrons or lose them?
anonymous
  • anonymous
Does that mean it's going gain 1 electron
Photon336
  • Photon336
yes exactly, how do you know?
anonymous
  • anonymous
because fluorine is not an ion, so it usually gain electrons, and also it's on the right side of the periodic table
Photon336
  • Photon336
yes, fluorine has a tendency to gain an electron because of it's position on the periodic table, and because of it's high electronegativity
anonymous
  • anonymous
But i still do not understand which noble gas does it represent. Isn't there is no charges for noble gas?
Photon336
  • Photon336
@claudia_lcl so that's right noble gases don't have charges, but an electron configuration can be similar to the noble gases. if fluorine gains say one electron take a look, what electron configuration does it represent now that it has 10 electrons? HINT: what element has 10 electrons on the periodic table |dw:1444012725958:dw|
Photon336
  • Photon336

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