If the following elements were to form ions, they would attain the same number of electrons as which noble gas?
elements: Be, Ca, Al, Rb, Se, F, P
noble gas: He, Ne, Ar, Kr
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You need to first identify what group those elements are in first
Beryllium and calcium are both in group 2. they are metals so they are going to lose 2 electrons. Calcium has 20 electrons and 20 protons, if it loses 2 electrons it's configuration resembles Argon.
Beryllium has 4 protons and 4 electrons. if it loses 2 electrons it has 2 electrons now and this configuration resembles helium.
Try fluorine and tell me what noble gas it would represent
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Fluorine has 9 protons and 9 electrons?
does it want to gain electrons or lose them?
Does that mean it's going gain 1 electron
yes exactly, how do you know?
because fluorine is not an ion, so it usually gain electrons, and also it's on the right side of the periodic table
yes, fluorine has a tendency to gain an electron because of it's position on the periodic table, and because of it's high electronegativity
But i still do not understand which noble gas does it represent. Isn't there is no charges for noble gas?
@claudia_lcl so that's right noble gases don't have charges, but an electron configuration can be similar to the noble gases.
if fluorine gains say one electron
take a look, what electron configuration does it represent now that it has 10 electrons?
HINT: what element has 10 electrons on the periodic table