A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

medal award please help!

  • This Question is Closed
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

  2. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    hint for the first part \[\Large \frac{13\pi}{12} = \frac{\pi+12\pi}{12}\] \[\Large \frac{13\pi}{12} = \frac{\pi}{12} + \frac{12\pi}{12}\] \[\Large \frac{13\pi}{12} = \frac{\pi}{12} + \pi\]

  3. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I'm not sure what it is that they want.. they are asking for the coordinates i'm a little lost :/

  4. amistre64
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    for a unit circle ... x = cos(t) y = sin(t)

  5. amistre64
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    but working them into their radical values might be a bit daunting :/

  6. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1444012468609:dw|

  7. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1444012481543:dw|

  8. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1444012492630:dw|

  9. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    add pi to pi/12 to get 13pi/12 this is the same as doing a 180 degree rotation |dw:1444012532760:dw|

  10. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    compare the two points marked on the unit circle the x coordinates are the same in magnitude, but they differ in sign (the first is positive, the second is negative) same for y coordinates

  11. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    that makes sense,.. so when they mention the terminal point p(x,y) how would I determine that?

  12. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    it's essentially point P but the signs are different for each coordinate

  13. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1444012707085:dw|

  14. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \[\Large P = \left(\frac{\sqrt{2+\sqrt{3}}}{2}, \frac{\sqrt{2-\sqrt{3}}}{2}\right)\]

  15. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \[\Large Q = \left(\color{red}{-}\frac{\sqrt{2+\sqrt{3}}}{2}, \color{red}{-}\frac{\sqrt{2-\sqrt{3}}}{2}\right)\]

  16. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so for 13pi/12 the terminal point would be -sqrt2+sqrt3/2?

  17. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    it would be point Q I wrote above

  18. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i'm a little confused :/

  19. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    all I did was take the coordinates of point P and make them negative

  20. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    point P is the point corresponding to pi/12 point Q is the point corresponding to 13pi/12

  21. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so how would I follow this pattern for 5pi/12?

  22. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Hint for part 2 5pi/12 = (pi + 4pi)/12 5pi/12 = pi/12 + 4pi/12 5pi/12 = pi/12 + pi/3 Then use these identities \[\Large \sin(x+y) = \sin(x)\cos(y)+\cos(x)\sin(y)\] \[\Large\cos(x+y) = \cos(x)\cos(y)-\sin(x)\sin(y)\]

  23. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I'm really lost..

  24. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I'm guessing you've never seen those identities before?

  25. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.