A community for students.
Here's the question you clicked on:
 0 viewing
FibonacciChick666
 one year ago
One card is selected from a standard deck of 52 cards. What is the probability that the card is either a diamond or a face card?
FibonacciChick666
 one year ago
One card is selected from a standard deck of 52 cards. What is the probability that the card is either a diamond or a face card?

This Question is Closed

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1there are 13 face cards right :P o,O hmm

FibonacciChick666
 one year ago
Best ResponseYou've already chosen the best response.1Looking for others' interpretations here. I thought it should be \(\frac{13}{52}+\frac{9}{52}=24/52=12/26=6/13\)

FibonacciChick666
 one year ago
Best ResponseYou've already chosen the best response.1I'm reading the problem wrong somehow(or book has a typeo)

FibonacciChick666
 one year ago
Best ResponseYou've already chosen the best response.1Yea, 13 face cards nosh

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1and 13 diamonds lol ??? no idea abt cards :P

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1some rules define aces as faces

FibonacciChick666
 one year ago
Best ResponseYou've already chosen the best response.1They say the answer is 13/52

FibonacciChick666
 one year ago
Best ResponseYou've already chosen the best response.1Made that mistake ( I defined an ace as a face first time around)

FibonacciChick666
 one year ago
Best ResponseYou've already chosen the best response.1but this is my second go

FibonacciChick666
 one year ago
Best ResponseYou've already chosen the best response.1Shouldn't the probability be greater than just diamonds if we have an or and not an XOR?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1if we remove all the face cards, and the diamonds, that is our ... outcome space?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.110+12 = 22 cards that are favored, out of 52 total

amistre64
 one year ago
Best ResponseYou've already chosen the best response.11thru9 jkq 9+12 = 18 ... out of 52 :)

FibonacciChick666
 one year ago
Best ResponseYou've already chosen the best response.1wait, only KQJ are face cards.... I think

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1XOR doesnt seem to translate well into english prose

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1its 11pm .. and i forgot how to add ... im going to bed :)

FibonacciChick666
 one year ago
Best ResponseYou've already chosen the best response.1lol, I am a bit confused by your argument. Let me attempt to understand

FibonacciChick666
 one year ago
Best ResponseYou've already chosen the best response.1we should have 30 cards not an option

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1dw:1444012968296:dw

FibonacciChick666
 one year ago
Best ResponseYou've already chosen the best response.13 suits, A10 each

FibonacciChick666
 one year ago
Best ResponseYou've already chosen the best response.1I added wrong above My conclusion should be 11/26

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1told you then i deleted the comment i thought this is impossible how fib can got it wrong lol

FibonacciChick666
 one year ago
Best ResponseYou've already chosen the best response.1lol I can't add today, clearly

FibonacciChick666
 one year ago
Best ResponseYou've already chosen the best response.1but still they are claiming 13/52 is the answer

FibonacciChick666
 one year ago
Best ResponseYou've already chosen the best response.1@ganeshie8 Would you say 13/52 is incorrect?

FibonacciChick666
 one year ago
Best ResponseYou've already chosen the best response.1I mean I think you proved it, but just want confirmation

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1A : diamonds B : face cards n(A) = 13 n(B) = 12 n(A \(\cap\) B) = 3 outcomes in favor = n(A \(\cup \) B) = n(A) + n(B)  n(A \(\cap\) B) = 13 + 12  3 = 22 total outcomes = 52 so p(A \(\cup\) B) = 22/52

FibonacciChick666
 one year ago
Best ResponseYou've already chosen the best response.1here is their argument: "The prob. that a card is either a diamond or a face card is determined as follows: Let D be the event the card is a diamond. Let F be the event the card is a face card. Then, Pr[D}=13/52 and Pr[F]=12/52. We want to compute the probability of the event DUF Pr[DUF]=Pr[D]+Pr[F]Pr[D(intersect)F]=13/52+12/523/13=13/52

FibonacciChick666
 one year ago
Best ResponseYou've already chosen the best response.1Ok, so book is def. wrong and I can't add... Great. Thanks guys!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.