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korosh23

  • one year ago

Pre-calculus 12 Question! The zeros of a function y= f(x) are -3 , 0 , 2. Determine the zeros of the function y= f (1 - x). a) -4, -1, 1 b) -3, -1 , 2 c) -2, 1 ,3 d) -1, 1 ,4

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  1. jim_thompson5910
    • one year ago
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    f(1-x) = f(-x+1) f(1-x) = f(-(x-1)) so the graph of f(x) is mirrored over the y axis and we shift 1 unit to the right to get the graph of f(1-x)

  2. korosh23
    • one year ago
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    @jim_thompson5910 so, the answer is a. Am I right?

  3. korosh23
    • one year ago
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    -(-3-1)= -4 for the domain?

  4. jim_thompson5910
    • one year ago
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    put another way, if x = -3, then f(-3) = 0 since we're told that -3 is a root so f(1-x) = f(1-(-3)) = f(1+3) = f(4) making 4 a root of f(1-x)

  5. korosh23
    • one year ago
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    Oh I see now. So any number inside the bracket of f( ) is a root of that function?

  6. jim_thompson5910
    • one year ago
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    `The zeros of a function y= f(x) are -3 , 0 , 2` -3 is a root of f(x) 0 is a root of f(x) 2 is a root of f(x)

  7. jim_thompson5910
    • one year ago
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    `-3 is a root of f(x)` ----> `f(-3) = 0` `0 is a root of f(x)` ----> `f(0) = 0` `2 is a root of f(x)` ----> `f(2) = 0`

  8. korosh23
    • one year ago
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    Right, thank you for clarifying it for me. :)

  9. jim_thompson5910
    • one year ago
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    sure thing

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