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diamondboy

  • one year ago

quick simple question

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  1. diamondboy
    • one year ago
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    |dw:1444013939779:dw|

  2. diamondboy
    • one year ago
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    |dw:1444013996457:dw|

  3. diamondboy
    • one year ago
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    find area of shaded portion

  4. diamondboy
    • one year ago
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    @Nnesha please could you help

  5. diamondboy
    • one year ago
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    I would medal can someone please help

  6. Nnesha
    • one year ago
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    tag jim :P :D first)gtg in few mints 2nd) not good at geometry :P

  7. diamondboy
    • one year ago
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    ok @jim_thompson5910 help

  8. Nnesha
    • one year ago
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    or ganeshie8 :D

  9. diamondboy
    • one year ago
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    @pooja195 @ganeshie8

  10. diamondboy
    • one year ago
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    help

  11. pooja195
    • one year ago
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    @Directrix @ganeshie8 @jim_thompson5910

  12. pooja195
    • one year ago
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    @zepdrix

  13. Nnesha
    • one year ago
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    well do you know how to find area of a circle ? i think you have to find area of a circle

  14. diamondboy
    • one year ago
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    yes I do but how do I go about that

  15. diamondboy
    • one year ago
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    Do I add the areas of the smaller circles and subtract it from that of the big circle

  16. diamondboy
    • one year ago
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    If thats d case what would be the radius of my big circle? 2?

  17. Nnesha
    • one year ago
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    radius of big woouldn't be 2 i guess :hmmm

  18. Nnesha
    • one year ago
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    *dies* l8r good luck cya

  19. diamondboy
    • one year ago
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    Ok

  20. diamondboy
    • one year ago
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    Thanks

  21. zepdrix
    • one year ago
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    |dw:1444014668003:dw|Is this what the problem looks like? :o the two circles are lined up vertically like this?

  22. diamondboy
    • one year ago
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    yes

  23. diamondboy
    • one year ago
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    byt the diameters, if extended, would be perpendicula to each other

  24. zepdrix
    • one year ago
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    |dw:1444014787277:dw|Ok cool :) Then I think you have the right idea. The larger radius is 2, and the smaller radii are each 1, ya?

  25. diamondboy
    • one year ago
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    ok

  26. diamondboy
    • one year ago
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    so the answer is 6.28?

  27. zepdrix
    • one year ago
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    Hmm that sounds right! :)\[\large\rm A=\pi (2)^2,\qquad\qquad a=\pi (1)^2\]\[\large\rm A-a-a=4\pi - 2\pi=2\pi\approx 6.28\]

  28. diamondboy
    • one year ago
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    |dw:1444014908723:dw|

  29. diamondboy
    • one year ago
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    thats how it actually looks like anyways

  30. Jhannybean
    • one year ago
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    \[A_{big}-(A_{c_1}+A_{c_2})= A_{shaded}\]

  31. diamondboy
    • one year ago
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    Ok thanks guys....I would have given you both a medal if I could

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