diamondboy
  • diamondboy
quick simple question
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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diamondboy
  • diamondboy
|dw:1444013939779:dw|
diamondboy
  • diamondboy
|dw:1444013996457:dw|
diamondboy
  • diamondboy
find area of shaded portion

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More answers

diamondboy
  • diamondboy
@Nnesha please could you help
diamondboy
  • diamondboy
I would medal can someone please help
Nnesha
  • Nnesha
tag jim :P :D first)gtg in few mints 2nd) not good at geometry :P
diamondboy
  • diamondboy
ok @jim_thompson5910 help
Nnesha
  • Nnesha
or ganeshie8 :D
diamondboy
  • diamondboy
@pooja195 @ganeshie8
diamondboy
  • diamondboy
help
pooja195
  • pooja195
@Directrix @ganeshie8 @jim_thompson5910
pooja195
  • pooja195
@zepdrix
Nnesha
  • Nnesha
well do you know how to find area of a circle ? i think you have to find area of a circle
diamondboy
  • diamondboy
yes I do but how do I go about that
diamondboy
  • diamondboy
Do I add the areas of the smaller circles and subtract it from that of the big circle
diamondboy
  • diamondboy
If thats d case what would be the radius of my big circle? 2?
Nnesha
  • Nnesha
radius of big woouldn't be 2 i guess :hmmm
Nnesha
  • Nnesha
*dies* l8r good luck cya
diamondboy
  • diamondboy
Ok
diamondboy
  • diamondboy
Thanks
zepdrix
  • zepdrix
|dw:1444014668003:dw|Is this what the problem looks like? :o the two circles are lined up vertically like this?
diamondboy
  • diamondboy
yes
diamondboy
  • diamondboy
byt the diameters, if extended, would be perpendicula to each other
zepdrix
  • zepdrix
|dw:1444014787277:dw|Ok cool :) Then I think you have the right idea. The larger radius is 2, and the smaller radii are each 1, ya?
diamondboy
  • diamondboy
ok
diamondboy
  • diamondboy
so the answer is 6.28?
zepdrix
  • zepdrix
Hmm that sounds right! :)\[\large\rm A=\pi (2)^2,\qquad\qquad a=\pi (1)^2\]\[\large\rm A-a-a=4\pi - 2\pi=2\pi\approx 6.28\]
diamondboy
  • diamondboy
|dw:1444014908723:dw|
diamondboy
  • diamondboy
thats how it actually looks like anyways
Jhannybean
  • Jhannybean
\[A_{big}-(A_{c_1}+A_{c_2})= A_{shaded}\]
diamondboy
  • diamondboy
Ok thanks guys....I would have given you both a medal if I could

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