projectile shot upward at 75m/s from a height of 10m off the grand. how long will it take for the projectile to be at ground level? What equation do I need to solve this problem?

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projectile shot upward at 75m/s from a height of 10m off the grand. how long will it take for the projectile to be at ground level? What equation do I need to solve this problem?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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try \[S = ut + \frac 1 2 at^2\]
@BAdhi I get 10m=75m/s(t)+4.9(t)^2 I'm confused on how to solve for 't'
in here the s and u are vectors.. and as convention they are positive upwards. According to the given information since the object is already place 10m higher, to reach the ground level the object has to go 10m downwardes thus S= -10m |dw:1444024565711:dw|

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also look into the sign of the acceleration also considering the direction convention ive used

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