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cheska_P

  • one year ago

projectile shot upward at 75m/s from a height of 10m off the grand. how long will it take for the projectile to be at ground level? What equation do I need to solve this problem?

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  1. BAdhi
    • one year ago
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    try \[S = ut + \frac 1 2 at^2\]

  2. cheska_P
    • one year ago
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    @BAdhi I get 10m=75m/s(t)+4.9(t)^2 I'm confused on how to solve for 't'

  3. BAdhi
    • one year ago
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    in here the s and u are vectors.. and as convention they are positive upwards. According to the given information since the object is already place 10m higher, to reach the ground level the object has to go 10m downwardes thus S= -10m |dw:1444024565711:dw|

  4. BAdhi
    • one year ago
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    also look into the sign of the acceleration also considering the direction convention ive used

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