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anonymous
 one year ago
The radius, r, of a circular cell changes with time t. If r(t) = ln(t+2), then the change in the area of the cell, ΔA, that occurs between t=0 and t=1 is given by ΔA = ∫ 2π ln(t+2)/t+2 dt. True or False? :/
anonymous
 one year ago
The radius, r, of a circular cell changes with time t. If r(t) = ln(t+2), then the change in the area of the cell, ΔA, that occurs between t=0 and t=1 is given by ΔA = ∫ 2π ln(t+2)/t+2 dt. True or False? :/

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triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1444022894691:dw

FibonacciChick666
 one year ago
Best ResponseYou've already chosen the best response.1So, what does an integral do?

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1444022983963:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1444023306505:dw

FibonacciChick666
 one year ago
Best ResponseYou've already chosen the best response.1I assume your integral in the question is not indefinite? @Clarence

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes, it's a definite integral, and I'm afraid I don't follow what triciaal has done... Sorry..

FibonacciChick666
 one year ago
Best ResponseYou've already chosen the best response.1so do integrals calculate area?

FibonacciChick666
 one year ago
Best ResponseYou've already chosen the best response.1yea. by definition they do

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Think of derivatives as finding a small incremental section of an area, and integrals are integrating that small section to find the total area made of those small, incremental sections.

FibonacciChick666
 one year ago
Best ResponseYou've already chosen the best response.1so now, integrals calculate area under the curve. In this instance we need the area of a circle.

FibonacciChick666
 one year ago
Best ResponseYou've already chosen the best response.1dw:1444024744065:dw

FibonacciChick666
 one year ago
Best ResponseYou've already chosen the best response.1and what jhanny elegantly put is the concept I am trying to illustrate

BAdhi
 one year ago
Best ResponseYou've already chosen the best response.0I think this question is an application of the question you posted in the following link http://openstudy.com/study#/updates/561204cae4b06b089598f6ab where \(f(r) =2\pi r\) and \(g(t) = \ln(t+2)\)

FibonacciChick666
 one year ago
Best ResponseYou've already chosen the best response.1^@BAdhi is correct. This is an application of the previous

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So what do I actually have to do to solve this one? Just follow on from what I did previously?

FibonacciChick666
 one year ago
Best ResponseYou've already chosen the best response.1yep, see if it was applied correctly

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay then, I'll try that thanks

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0After going through the same process that BAdhi did previously, it seems right to me

FibonacciChick666
 one year ago
Best ResponseYou've already chosen the best response.1I agree. Make sure you show your work with it on your paper :)
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