A community for students.
Here's the question you clicked on:
 0 viewing
cassieforlife5
 one year ago
Find the limit as x approaches 1
cassieforlife5
 one year ago
Find the limit as x approaches 1

This Question is Closed

cassieforlife5
 one year ago
Best ResponseYou've already chosen the best response.0dw:1444032099173:dw

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.5\[\large \lim_{x\rightarrow 1} \frac{\dfrac{1}{\sqrt{1+x}}1}{x}\]

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.5Well, let's try a two sided limit approach.

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.5So the first would be \(x\rightarrow (1)^\) and the second approach would be \(x\rightarrow (1)^+\)

cassieforlife5
 one year ago
Best ResponseYou've already chosen the best response.0okay I normally plug these into the calculator and use the table, but I'm not sure how I should insert it into the calculator

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.5Well, you simply need to find a number that is incrementally smaller than 1 from the left,...like.... 0.9999

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.5Then from the right, you could choose a number that incrementally bigger than 1, like... 1.00001

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.5The value you get will essentially tell you whether your limit is approaching \(+\infty\) or \(\infty\)

cassieforlife5
 one year ago
Best ResponseYou've already chosen the best response.0I'm having trouble including the actual equation. Now i'm putting in: \[\left( \left( 1\div \sqrt{1+\chi} \right))\div \chi \right)(1\div \chi)\] But I don't think it's right

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.5So how I would input into the calculator: \[\large \frac{((1)/(\sqrt{10.99999} ) 1))}{(0.99999)}\]

cassieforlife5
 one year ago
Best ResponseYou've already chosen the best response.0it says error which is the problem that I had before as well :( I've tried phrasing the equation differently too

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.5Might be the lack or the total amount of parenthesis.

cassieforlife5
 one year ago
Best ResponseYou've already chosen the best response.0hmm i don't know. I can't think of any other way to insert it though

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.5I'll show you in a second, let me just upload a picture so I can insert it here.

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.5Take a look at that.

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.5Hm.. as @iambatman stated earlier, what if we were to simplify the function a little?

cassieforlife5
 one year ago
Best ResponseYou've already chosen the best response.0okay I got an answer from that and I'm working on a few of the other values

cassieforlife5
 one year ago
Best ResponseYou've already chosen the best response.0wait wouldn't you need another parentheses after the 1? or is that what was messing me up before

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.5yeah that's why I'm figuring out how to make this equation more manageable.

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.5\[\begin{align} \lim_{x\rightarrow (1)^} \frac{\dfrac{1}{\sqrt{1+x}}1}{x} \qquad &\implies\lim_{x\rightarrow (1)^} \frac{1\sqrt{1+x}}{x\sqrt{1+x}} \\ & \implies \lim_{x\rightarrow (1)^} \frac{1}{x\sqrt{1+x}} \frac{1}{x} \end{align} \]

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.5I've got to head off, good luck figuring this out!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.