ParthKohli
  • ParthKohli
two numbers are randomly chosen from 1, 3, 5, 7, ..., 145, 147, 149
Mathematics
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SOLVED
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jamiebookeater
  • jamiebookeater
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ParthKohli
  • ParthKohli
in how many ways can they be chosen so that we have their product divisible by 5?
ParthKohli
  • ParthKohli
Total numbers: 75. Numbers divisible by 5: 15. Case-I: One number and only one number of the two chosen ones is divisible by 5. \(15\) numbers divisible by 5 and \(60 \) numbers that are not. Thus there are \(15\cdot 60= 900\) such pairs. Case-II: Both numbers divisible by 5.\[\binom{15}{2}=105\]Total numbers: 1005.
ParthKohli
  • ParthKohli
The given answer is 1020. Am I missing something?

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mathmath333
  • mathmath333
\(\color{white}{bookmark}\)
ParthKohli
  • ParthKohli
oooh, goddammit. you know what, the original question has a list that goes up to 151 :P
ParthKohli
  • ParthKohli
in that case, divisible by 5: 15... total: 76
ParthKohli
  • ParthKohli
so I'm right in a way. I just read the list till 149 lol

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