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mathmath333
 one year ago
How many even natural numbers divisible by 5
can be formed with digits 0,1,2,3,4,5,6
(if repetition is not allowed)
mathmath333
 one year ago
How many even natural numbers divisible by 5 can be formed with digits 0,1,2,3,4,5,6 (if repetition is not allowed)

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mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0\(\large \color{black}{\begin{align} & \normalsize \text{ How many even natural numbers divisible by 5}\hspace{.33em}\\~\\ & \normalsize \text{ can be formed with digits 0,1,2,3,4,5,6}\hspace{.33em}\\~\\ & \normalsize \text{ (if repetition is not allowed)}\hspace{.33em}\\~\\ & a.)\ 1957 \hspace{.33em}\\~\\ & b.)\ 1956 \hspace{.33em}\\~\\ & c.)\ 1236 \hspace{.33em}\\~\\ & d.)\ 1235 \hspace{.33em}\\~\\ \end{align}}\)

BAdhi
 one year ago
Best ResponseYou've already chosen the best response.1its not infinity since reptition is not allowed... the last digit has to be either 0 or 5 to be divisible by 5. since it also has to be even the only number that can be finished with is 0 so now the last digit is fixed to 0 there are 6 more digits that can be used to form 1,2,3,4,5,6 digit number plus 0 the last dgit 1digit + 0 > 6 2digits + 0 > 6.5 ....

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0\(\large \color{black}{\begin{align} \text{0} & \rightarrow 0 \hspace{.33em}\\~\\ \text{ _.0} & \rightarrow 6 \hspace{.33em}\\~\\ \text{ _._.0} & \rightarrow 30 \hspace{.33em}\\~\\ \text{ _._._.0} & \rightarrow 120 \hspace{.33em}\\~\\ \text{ _._._._.0} & \rightarrow 360 \hspace{.33em}\\~\\ \text{ _._._._._.0} & \rightarrow 720 \hspace{.33em}\\~\\ \text{ _._._._._._.0} & \rightarrow 720 \hspace{.33em}\\~\\ total & =1956 \hspace{.33em}\\~\\ \end{align}}\)

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0i hope this is correct
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