anonymous
  • anonymous
Please help! :) Suppose you start at the point (1,0) on a unit circle and move some distance t along the circle to the terminal point P(8/17,15/17). What would the exact coordinates of the terminal point be if you had instead moved: a distance t+π? Terminal Point would be at P( , ) a distance t+2π? Terminal Point would be at P( , ) a distance −t? Terminal Point would be at P( , ) No decimals! Hint: make a sketch of the unit circle and t.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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welshfella
  • welshfella
|dw:1444049973408:dw|
welshfella
  • welshfella
|dw:1444050159383:dw|
welshfella
  • welshfella
the point P corresponds to the angle pi + t

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welshfella
  • welshfella
so what do you think the coordinates of P are?
anonymous
  • anonymous
the coordinates of p for the first one are (-sqrt3/2,-1/2)
welshfella
  • welshfella
???? I don't understand that
anonymous
  • anonymous
or maybe it's just negative (-8/17,-15/17)
welshfella
  • welshfella
yes
anonymous
  • anonymous
|dw:1444050664116:dw|
welshfella
  • welshfella
that is correct
anonymous
  • anonymous
for 2pi would it be something like this?
welshfella
  • welshfella
No 2pi is a complete circle P would come back to the same place
welshfella
  • welshfella
what you have drawn is - t
welshfella
  • welshfella
now you have all the answers
welshfella
  • welshfella
|dw:1444050837502:dw|
anonymous
  • anonymous
which would be 8/17,-15/17 :)
welshfella
  • welshfella
Yes that is correct for -t
anonymous
  • anonymous
so what if the distance would be t +pi/2?
welshfella
  • welshfella
the same as for t
welshfella
  • welshfella
|dw:1444050987885:dw|
anonymous
  • anonymous
thanks! :) and for t-pi/2 is that just negative?
welshfella
  • welshfella
t - pi/2 will take you back to t + pi/2
welshfella
  • welshfella
- the first part
hartnn
  • hartnn
\(\color{blue}{\text{Originally Posted by}}\) @sana97 so what if the distance would be t +pi/2? \(\color{blue}{\text{End of Quote}}\) \(\color{blue}{\text{Originally Posted by}}\) @welshfella the same as for t \(\color{blue}{\text{End of Quote}}\) if the distance is t+ pi/2, the co-ordinates will not be same as that of 't'. I think welshfella mistook it for t +2pi ... |dw:1444057152219:dw|
hartnn
  • hartnn
|dw:1444057237116:dw|
welshfella
  • welshfella
ah yes My mistake..

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