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anonymous

  • one year ago

Please help! :) Suppose you start at the point (1,0) on a unit circle and move some distance t along the circle to the terminal point P(8/17,15/17). What would the exact coordinates of the terminal point be if you had instead moved: a distance t+π? Terminal Point would be at P( , ) a distance t+2π? Terminal Point would be at P( , ) a distance −t? Terminal Point would be at P( , ) No decimals! Hint: make a sketch of the unit circle and t.

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  1. welshfella
    • one year ago
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    |dw:1444049973408:dw|

  2. welshfella
    • one year ago
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    |dw:1444050159383:dw|

  3. welshfella
    • one year ago
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    the point P corresponds to the angle pi + t

  4. welshfella
    • one year ago
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    so what do you think the coordinates of P are?

  5. anonymous
    • one year ago
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    the coordinates of p for the first one are (-sqrt3/2,-1/2)

  6. welshfella
    • one year ago
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    ???? I don't understand that

  7. anonymous
    • one year ago
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    or maybe it's just negative (-8/17,-15/17)

  8. welshfella
    • one year ago
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    yes

  9. anonymous
    • one year ago
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    |dw:1444050664116:dw|

  10. welshfella
    • one year ago
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    that is correct

  11. anonymous
    • one year ago
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    for 2pi would it be something like this?

  12. welshfella
    • one year ago
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    No 2pi is a complete circle P would come back to the same place

  13. welshfella
    • one year ago
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    what you have drawn is - t

  14. welshfella
    • one year ago
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    now you have all the answers

  15. welshfella
    • one year ago
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    |dw:1444050837502:dw|

  16. anonymous
    • one year ago
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    which would be 8/17,-15/17 :)

  17. welshfella
    • one year ago
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    Yes that is correct for -t

  18. anonymous
    • one year ago
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    so what if the distance would be t +pi/2?

  19. welshfella
    • one year ago
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    the same as for t

  20. welshfella
    • one year ago
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    |dw:1444050987885:dw|

  21. anonymous
    • one year ago
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    thanks! :) and for t-pi/2 is that just negative?

  22. welshfella
    • one year ago
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    t - pi/2 will take you back to t + pi/2

  23. welshfella
    • one year ago
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    - the first part

  24. hartnn
    • one year ago
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    \(\color{blue}{\text{Originally Posted by}}\) @sana97 so what if the distance would be t +pi/2? \(\color{blue}{\text{End of Quote}}\) \(\color{blue}{\text{Originally Posted by}}\) @welshfella the same as for t \(\color{blue}{\text{End of Quote}}\) if the distance is t+ pi/2, the co-ordinates will not be same as that of 't'. I think welshfella mistook it for t +2pi ... |dw:1444057152219:dw|

  25. hartnn
    • one year ago
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    |dw:1444057237116:dw|

  26. welshfella
    • one year ago
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    ah yes My mistake..

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