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So integrate 64-25x^2? @irishboy123

\(Width = 64-25x^2\)
\(Height = 64-25x^2\)
\(A(x) = W \cdot H = (64-25x^2)^2\)

Oh really? I got area to be \[\frac{ 4(64-x) }{ 25 }\]

And then integrating that from 0 to 1 to get 254/25 as my answer?

Sorry, x was meant to be y, my bad.

|dw:1444053041996:dw|

Oh yeah, that makes sense! Did you accidentally delete your previous reply? :P

Thanks again for your help! Much appreciated :)

oh i see
the 2 is because it is both sides of the y axis....

So the answer is actually 8192/25? Go figure :p

\[=\dfrac{8192}{25}\]

Sweet, mystery solved!

thank you for your patience, have we licked it?!?!

I think we have! Always a pleasure working with you Mr. Holmes :p :)

thank you Dr Watson, and vice versa :-))