undeadknight26
  • undeadknight26
Help where did I go wrong?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
undeadknight26
  • undeadknight26
If you chose translation, use the coordinates of your transformation along with the distance formula to show that the two triangles are congruent by the SSS postulate. You must show all work with the distance formula and each corresponding pair of sides to receive full credit.
undeadknight26
  • undeadknight26
(x + 5, y + 5): A: (3, 2), B: (11, 8), C: (11, 2) A = (-2, -3) = (-2 + 5, -3 + 5) = (3, 2) B = (6, 3) = (6 + 5, 3 + 5) = (11, 8) C = (6, -3) = (6 + 5, -3 + 5) = (11, 2)
undeadknight26
  • undeadknight26
D = sqrt((x2 – x1)^2 + (y2 – y1)^2) D = sqrt(((-2) – 6)^2 + ((-3) – (-3))^2) D = sqrt((-8)^2 + (0)^2) D = sqrt(64 + 0) D = sqrt(64) D = 8 AB D = sqrt((x2 – x1)^2 + (y2 – y1)^2) D = sqrt((11 – 3)^2 + (8 – 2)^2) D = sqrt((8)^2 + (6)^2) D = sqrt((64) + (36)) D = sqrt(100) D = 10 DE AB and DE do not equal each other? They're supposed to. Can you see any faults in my work?

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undeadknight26
  • undeadknight26
DE and BC are equal... D = sqrt((x2 – x1)^2 + (y2 – y1)^2) D = sqrt((11 – 3)^2 + (8 – 2)^2) D = sqrt((8)^2 + (6)^2) D = sqrt((64) + (36)) D = sqrt(100) D = 10 DE D = sqrt((x2 – x1)^2 + (y2 – y1)^2) D = sqrt((6 – (-2))^2 + (3 – (-3)^2)) D = sqrt((8)^2 + (6)^2) D = sqrt((64) + (36)) D = sqrt(100) D = 10 BC
undeadknight26
  • undeadknight26
@texaschic101 @Abhisar @aaronq @AaronAndyson @triciaal @KendrickLamar2014 @zepdrix @CallMeKiki Please help.
anonymous
  • anonymous
In the second line of your calculation you have D = sqrt(((-2) – 6)^2 + ((-3) – (-3))^2) when you should have D = sqrt(((-2) – 6)^2 + ((-3) – (3))^2)
undeadknight26
  • undeadknight26
THANK YOU SO MUCH GOOD SIR! You seriously do not know how much you just helped me! I've been racking my brain on this for like an hour!

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