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undeadknight26

  • one year ago

Help where did I go wrong?

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  1. undeadknight26
    • one year ago
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    If you chose translation, use the coordinates of your transformation along with the distance formula to show that the two triangles are congruent by the SSS postulate. You must show all work with the distance formula and each corresponding pair of sides to receive full credit.

  2. undeadknight26
    • one year ago
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    (x + 5, y + 5): A: (3, 2), B: (11, 8), C: (11, 2) A = (-2, -3) = (-2 + 5, -3 + 5) = (3, 2) B = (6, 3) = (6 + 5, 3 + 5) = (11, 8) C = (6, -3) = (6 + 5, -3 + 5) = (11, 2)

  3. undeadknight26
    • one year ago
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    D = sqrt((x2 – x1)^2 + (y2 – y1)^2) D = sqrt(((-2) – 6)^2 + ((-3) – (-3))^2) D = sqrt((-8)^2 + (0)^2) D = sqrt(64 + 0) D = sqrt(64) D = 8 AB D = sqrt((x2 – x1)^2 + (y2 – y1)^2) D = sqrt((11 – 3)^2 + (8 – 2)^2) D = sqrt((8)^2 + (6)^2) D = sqrt((64) + (36)) D = sqrt(100) D = 10 DE AB and DE do not equal each other? They're supposed to. Can you see any faults in my work?

  4. undeadknight26
    • one year ago
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    DE and BC are equal... D = sqrt((x2 – x1)^2 + (y2 – y1)^2) D = sqrt((11 – 3)^2 + (8 – 2)^2) D = sqrt((8)^2 + (6)^2) D = sqrt((64) + (36)) D = sqrt(100) D = 10 DE D = sqrt((x2 – x1)^2 + (y2 – y1)^2) D = sqrt((6 – (-2))^2 + (3 – (-3)^2)) D = sqrt((8)^2 + (6)^2) D = sqrt((64) + (36)) D = sqrt(100) D = 10 BC

  5. undeadknight26
    • one year ago
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    @texaschic101 @Abhisar @aaronq @AaronAndyson @triciaal @KendrickLamar2014 @zepdrix @CallMeKiki Please help.

  6. anonymous
    • one year ago
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    In the second line of your calculation you have D = sqrt(((-2) – 6)^2 + ((-3) – (-3))^2) when you should have D = sqrt(((-2) – 6)^2 + ((-3) – (3))^2)

  7. undeadknight26
    • one year ago
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    THANK YOU SO MUCH GOOD SIR! You seriously do not know how much you just helped me! I've been racking my brain on this for like an hour!

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