Find the exact value of cos-1the quantity square root of three divided by two.

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Find the exact value of cos-1the quantity square root of three divided by two.

Mathematics
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\[\cos^{-1} (\sqrt{3}/2)\]
we take inverse of ratio to find an angle so you need an angle when cos theta = sqrt{3}/2 1st) you can use unit circle 2nd) calculator 3rd) familiar with 30-6-90 /45-45-90 triangle theorem
btw in the order pair (x,y) cos = x sin = y

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so what do i do next
1st) you can use unit circle 2nd) calculator 3rd) familiar with 30-6-90 /45-45-90 triangle theorem 3 ways to find an answer pick one :=)
it's 30-60-90 ****
unit circle i guess
alright |dw:1444053304744:dw| at what angle cos = sqrt{3}/2
30 and 60
no just 30
there should be two angle when cos =sqrt{3}/2 remember it's reflected over they axis |dw:1444053390030:dw|
the*
i thought you only needed one but okay then 330
well there are two you should write both as an ansaawer just in case if they are looking for more than one value hmm
okay so whats the next step?
that's it
is there any statement about degree or radian ? i mean answer should be in degree or radian ?
but its the arc cosine
its a radian
right when we need an angle we take invs of ratio so that's why it's arccos
ohh okay formula to convert degree to radian \[\huge\rm rad=\frac{ \pi}{ 180} \times degree \]
well which angle do i use
both angles 30 and 330
cant i just use the radian it has on the unit circle next to it
yes you can
you will get the same answer
but both are an answer choice
which one is right
ohh so you can pick only one ?
yes
i'll pick 30 bec that's the angle where it starts
330 is areflection
so pi/6?
looks good
thank you
yw

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