## DF001 one year ago Help with Algebra -3y-10=-y^2

1. DF001

|dw:1444058324628:dw|

2. DF001

|dw:1444058441020:dw|

3. DF001

|dw:1444058541972:dw|

4. DF001

please check if i am correct

5. phi

This step should be fixed |dw:1444059219806:dw|

6. phi

The rest looks ok. 10 + 9/4 is 40/4 + 9/4 = 49/4 and $y^2 - \frac{3}{2}y + \frac{3^2}{2^2} = \frac{49}{4}$ the left side is a perfect square $(y-\frac{3}{2})^2= \frac{49}{4}$ take the square root of both sides $y - \frac{3}{2} = \pm\frac{7}{4}$ add 3/2 to both sides to find y $y= \frac{3}{2} \pm \frac{7}{4}$ that can also be written as $y = \frac{6\pm7}{4}$ or y= -1/4 and y= 13/4