clamin
  • clamin
What is the 11th term of the following geometric sequence? 7/9, -7/3,  7, -21, 63
Mathematics
jamiebookeater
  • jamiebookeater
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

clamin
  • clamin
The choices are  a. 15,309 b. -15, 309 c. -45, 927 d. 45,927
Nnesha
  • Nnesha
do you know how to find common ration or what is common ratio ?
clamin
  • clamin
The gap of two numbers

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Nnesha
  • Nnesha
to find common ratio you can divide next term with the previous one \[\large\rm r=\frac{ a_2 }{ a_1} ~~ or~~\frac{ a_3 }{ a_2 } ~~or ~~\frac{ a_4 }{ a_3 }\] then use the general form of geometeric sequence \[\huge\rm a_n = a_1 \times (r)^{n-1} \] a_1 = first term n = number of term that u have to find r= ratio

Looking for something else?

Not the answer you are looking for? Search for more explanations.