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clamin

  • one year ago

What is the 11th term of the following geometric sequence? 7/9, -7/3,  7, -21, 63

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  1. clamin
    • one year ago
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    The choices are  a. 15,309 b. -15, 309 c. -45, 927 d. 45,927

  2. Nnesha
    • one year ago
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    do you know how to find common ration or what is common ratio ?

  3. clamin
    • one year ago
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    The gap of two numbers

  4. Nnesha
    • one year ago
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    to find common ratio you can divide next term with the previous one \[\large\rm r=\frac{ a_2 }{ a_1} ~~ or~~\frac{ a_3 }{ a_2 } ~~or ~~\frac{ a_4 }{ a_3 }\] then use the general form of geometeric sequence \[\huge\rm a_n = a_1 \times (r)^{n-1} \] a_1 = first term n = number of term that u have to find r= ratio

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