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anonymous97
 one year ago
A ball is thrown from a height of
32
meters with an initial downward velocity of
2/ms
. The ball's height
h
(in meters) after
t
seconds is given by the following.
=h−32−2t5t^2
How long after the ball is thrown does it hit the ground?
Round your answer(s) to the nearest hundredth.
anonymous97
 one year ago
A ball is thrown from a height of 32 meters with an initial downward velocity of 2/ms . The ball's height h (in meters) after t seconds is given by the following. =h−32−2t5t^2 How long after the ball is thrown does it hit the ground? Round your answer(s) to the nearest hundredth.

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zpupster
 one year ago
Best ResponseYou've already chosen the best response.10=−32−2t+5t2 when the ball hits the ground h=0 5t2 2t  32 = 0 rearranging solve this with quadratic formula \[b \pm \frac{ \sqrt { b^24ac} }{ 2a }\]

zpupster
 one year ago
Best ResponseYou've already chosen the best response.1take the negative answer becasue the balls traveling in a downward direction. Run a check
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