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Ok so we have:
\[ N(t)=N_o e^{-kt}\]

yes but it says find the age of the skull to the nearest year.

Taking the ln of both sides:
\[\ln(0.63)= -(0.0001 yr^{-1})t\]

Divide and you have you answer

divide 0.63 / -0.0001?

Please note it isnt 0.63 but ln(0.63)

And then it is a yes

i got -6300

natrual log of 0.63 divided by -10^-4

your confusing me

What do you find confusing?

Please, I cant help if I dont know where your getting confused.

show him the steps in detail

I was under the impression I did alekos but I will go through it again.

Ok so we given in the problem that the amount of C14 we find in the skull is 63%

This results in the equation I gave above:
\[63\% = 0.63=e^{-kT}\]

im on a diffrent question now

So what did you get for the last one?

i got it wrong that was my last question but i passed the test

dont bother plasma, seems like you're wasting you're time