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jessie13
 one year ago
Will Medal Answer ASAP!!!!!
1: What is the GCF of the numerator and denominator in the following fraction? 21m^2n/28mn^2
7m^2n^2
7mn
21m^3n^3
mn
jessie13
 one year ago
Will Medal Answer ASAP!!!!! 1: What is the GCF of the numerator and denominator in the following fraction? 21m^2n/28mn^2 7m^2n^2 7mn 21m^3n^3 mn

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so whats the question?

jessie13
 one year ago
Best ResponseYou've already chosen the best response.0im putting it up right now!

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1So this is what we have right @jessie13 \[\frac{ 21m ^{2}n }{ 28mn ^{2} }\]

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1so greatest common factor, is the largest number that can go into both the numerator and denominator

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1Let's break this up into two parts

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{ 21 }{ 28 } * (\frac{ m ^{2}n }{ mn ^{2} })\]

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1do you know how to subtract powers?

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1whenever we divide exponents we subtract the exponents. so we will do that first \[\frac{ m ^{2}n}{ mn ^{2} } = Numerator[ m ^{2}m ^{1} = m] denominator [n ^{1}n ^{2}] = n ^{1}\] we simplify the variables first. \[\frac{ m }{ n }\]

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1@jessie13 so now this is what we have we need to find the greatest common factor so it has to be the largest number that goes into both 21 and 28 \[\frac{ 21 }{ 28 } *(\frac{ m }{ n })\]

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1@jessie13 yep :) here's why. and that's why I told you to do it that way yeah so dw:1444067072198:dw

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{ 3 m}{ 4 n} * *\frac{ 7 mn}{ 7 mn } = \frac{ 21 }{ 28 } \frac{ m*m = m ^{2}n }{n*n = n ^{2}m }\]

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1\[(7mn) = GCF\] because if we multiply this by 3m/4n we get what we started with @jessie13 look at this tell me if this makes sense to you

jessie13
 one year ago
Best ResponseYou've already chosen the best response.0ya it makes more sense thanks!

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1can you show me why this makes sense @jessie13 ?
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