A community for students.
Here's the question you clicked on:
 0 viewing
Mitchi35
 one year ago
I'm only 16 and I am doing some AP calculus problems... Anyone good or somewhat okay at it?
Mitchi35
 one year ago
I'm only 16 and I am doing some AP calculus problems... Anyone good or somewhat okay at it?

This Question is Closed

sleepyhead314
 one year ago
Best ResponseYou've already chosen the best response.1We got plenty of people that can help you here :) I got a 5 on both the AB and BC calc tests ^_^

Mitchi35
 one year ago
Best ResponseYou've already chosen the best response.0Oh wow! Okay I'm sold. Let me just put the problem up real quick.

Mitchi35
 one year ago
Best ResponseYou've already chosen the best response.0Give the volume of the solid generated by revolving the region bounded by the graph of y = ln(x), the xaxis, the lines x = 1 and x = e, about the yaxis.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What is the derivatives of: \[x^{3}\] and \[ e^{2x}\] with respect to x?

sleepyhead314
 one year ago
Best ResponseYou've already chosen the best response.1haha @PlasmaFuzer I would suggest that you ask your own questions in the "Ask a question..." box to the left ^_^

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ooo I like the question even better @Mitchi35

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@sleepyhead314 I thought he was asking for us to quiz him... I have many more where that came from, but I guess I just misunderstood what he was looking for

Mitchi35
 one year ago
Best ResponseYou've already chosen the best response.0Lol What are yo talking about? @PlasmaFuzer

sleepyhead314
 one year ago
Best ResponseYou've already chosen the best response.1I see, it's fine xD but feel free to jump in to help anytime @PlasmaFuzer :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I didn't see your second post until I had already posted mine, and then I confused you for the the other person in here and not the poster XD sorry.

sleepyhead314
 one year ago
Best ResponseYou've already chosen the best response.1now, I'm guessing you Are allowed a graphing calculator for this problem? @Mitchi35

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I would @sleepyhead314 but I am afraid its been quite a while for me on these types of problems so I think I might just cheat step my way to the answer which isn't instructive if you don't understand why things work the way they do

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I.e. just integrate and rotate

Mitchi35
 one year ago
Best ResponseYou've already chosen the best response.0And I'm a she by the way.@ PlasmaFuzer. And Yes. But only I don't have one. @sleepyhead314

sleepyhead314
 one year ago
Best ResponseYou've already chosen the best response.1dw:1444067181310:dw

Mitchi35
 one year ago
Best ResponseYou've already chosen the best response.0Oh wait! They have multiple choice. I"ll put them up.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't want to step on any toes @sleepyhead314 but I am also curious to see if I remembered correctly can I give it a shot and if I am wrong then you can correct?

sleepyhead314
 one year ago
Best ResponseYou've already chosen the best response.1of course @PlasmaFuzer feel free to take the wheel ^_^

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I am mostly just debating between two approaches, my gut tells me you calculate the integral of the function (i.e. area under curve), then you rotate that 2pi radians about the xaxis....

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Then again I have to consider that the infinitesimal areal elements are circles of radius ln(x) and so my integrand should be ln(x)^2 (i.e. imitate the circle formula)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Considering further I think it should be the first, because the integral derivation of the area of a circle involves the circumference as the integrand.... therefore my first approach I believe to be correct.

jigglypuff314
 one year ago
Best ResponseYou've already chosen the best response.1try the disk method, volume = pi times the integral of the function from bound to bound squared

jigglypuff314
 one year ago
Best ResponseYou've already chosen the best response.1in this case your function is ln(x) and your bounds are from 1 to e

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ahh yes ty jiggly Its the square of the integral not the integrand squared that makes more sense.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You can take this one Im obviously rusty

Mitchi35
 one year ago
Best ResponseYou've already chosen the best response.0Yeah. It's fine guys. I'll just ask the teacher. Thank you very much though anyways. :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh @Mitchi35 I can help if they left.... I realized my mistake, and if they aren't there to help finish the problem I am more than able.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I just was gonna give them first crack since I kinda screwed up.... Anyways think of the problem as assembling a bunch of disks whose area is given by pi*r^2 where the radius in this instance will be an really thing slice of the area under the curve.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok @Mitchi35 I was right before I just pulled up a quick review site and it isnt the integral squard as jigglypuff suggested but it is the INTEGRAND squared prior to integration. Give me a moment and I will type up a solution.

jigglypuff314
 one year ago
Best ResponseYou've already chosen the best response.1sorry if our explanations are a little confusing @Mitchi35 I'll attach the answer I got for your question on this comment for you hopefully that might help a bit more :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh yeah @jigglypuff314 if thats what you meant I totally agree.... I was torn between my first two approaches and thought what you said was implying a third.... but really it was just confirming the second approach.

jigglypuff314
 one year ago
Best ResponseYou've already chosen the best response.1I was simply using the approach that my BC calc teacher taught me :P
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.