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Here's a picture of the problem

You could pay for Qualified Help.

I don't have the money

Still need help @rosebud4612flvs ? ^_^

I think I'm good; When I did it by myself I got x^2+2x-1=0

You have probably missed a (-1) from the second equation.

I don't have money for a QH

don wrry :)

^ agreed ^_^

Okay, so I know it's not C or D

The one's would cancel out right?

which would leave B?

@just_one_last_goodbye
Are you suggesting that non QH will give a wrong answer and QH will not?

\[-4x+1=y=2x^2-1\]\[-4x+1=2x^2-1\]can u find the answer now :)

Follow what @imqwerty is working out for you.
We're using the same method.
@rosebud4612flvs

Yes, I understand that step. What do I do next?

Do I have to combine the x's?

Okay so would I do 2x^2-1+(-4x+1)?

ugh

I think I did that wrong

@just_one_last_goodbye
whew! it's a little more clear!

yes :) its correct so now u have this-\[-4x+1-(-4x+1)=2x^2 - 1 -(-4x+1)\] now open the brackets

okay so the first part cancels out

and that leaves me with 2(x^2−1+2x)

is that correct?

yes and what about the right hand side

is it 2(x^2−1+2x)

would it be C?

x^2+2x-1=0

no, what did u get on opening the bracket on the right hand side?

on the right hand side I got 2(x2−1+2x)

should it have been 2x^2-1+4x+1?

oh wait forget that

THANK YOU SO MUCH

have u understood how we got the answer ?

It was correct :) and I understand it so much better now thank you

np (: