I REALLY NEED HELP, IT'S AN EMERGENCY!! WILL MEDAL

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I REALLY NEED HELP, IT'S AN EMERGENCY!! WILL MEDAL

Mathematics
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I don't have the money

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Still need help @rosebud4612flvs ? ^_^
Solve by comparison, y=2x^2-1 y=-4x+1 Since both right-hand sides equal to y, you only have to equate them to get: (y=)2x^2-1=-4x+1 Transpose terms to get an expression ....=0 which matches one of the answers.
I think I'm good; When I did it by myself I got x^2+2x-1=0
You have probably missed a (-1) from the second equation.
No problem ^_^ we believe everyone deserves an education but... it would be nice if you could get some qualified helper to help :) see... the people helping can give you a wrong answer but our QH help with a 100% step by step help and we can assure you that the answer will be correct (or your money back)
I don't have money for a QH
don wrry :)
^ agreed ^_^
Okay, so I know it's not C or D
The one's would cancel out right?
which would leave B?
@just_one_last_goodbye Are you suggesting that non QH will give a wrong answer and QH will not?
\[-4x+1=y=2x^2-1\]\[-4x+1=2x^2-1\]can u find the answer now :)
?
@mathmate is B correct?
Follow what @imqwerty is working out for you. We're using the same method. @rosebud4612flvs
ok we know that- \[y=-4x+1\]and also that\[y=2x^2-1\] so -4x+1 and 2x^2-1 are both equal to y so they both are equal so we can write\[-4x+1=2x^2-1\]did u understand this step?@rosebud4612flvs
Yes, I understand that step. What do I do next?
Do I have to combine the x's?
@mathmate I am stating that some non QH will probably give you a direct answer. and it might be wrong. Not all tho ^_^ Forgive me if I said it wrong
Okay so would I do 2x^2-1+(-4x+1)?
ugh
I think I did that wrong
@just_one_last_goodbye whew! it's a little more clear!
yes :) its correct so now u have this-\[-4x+1-(-4x+1)=2x^2 - 1 -(-4x+1)\] now open the brackets
okay so the first part cancels out
and that leaves me with 2(x^2−1+2x)
is that correct?
yes and what about the right hand side
is it 2(x^2−1+2x)
would it be C?
x^2+2x-1=0
no, what did u get on opening the bracket on the right hand side?
on the right hand side I got 2(x2−1+2x)
yes that is correct :D so now we have- \[0=2(x^2-1+2x)\]opening the bracket u get-\[0=2(x^2)+2(-1)+2(2x)\]\[0=2x^2-2+4x\] thas ur answer :)
should it have been 2x^2-1+4x+1?
oh wait forget that
THANK YOU SO MUCH
have u understood how we got the answer ?
It was correct :) and I understand it so much better now thank you
np (:

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