I REALLY NEED HELP, IT'S AN EMERGENCY!! WILL MEDAL

- anonymous

I REALLY NEED HELP, IT'S AN EMERGENCY!! WILL MEDAL

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- schrodinger

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- anonymous

Here's a picture of the problem

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- Preetha

You could pay for Qualified Help.

- anonymous

I don't have the money

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## More answers

- anonymous

@ganeshie8 @mathmate @paki @rishavraj @Bookworm14

- just_one_last_goodbye

Still need help @rosebud4612flvs ? ^_^

- mathmate

Solve by comparison,
y=2x^2-1
y=-4x+1
Since both right-hand sides equal to y, you only have to equate them to get:
(y=)2x^2-1=-4x+1
Transpose terms to get an expression ....=0 which matches one of the answers.

- anonymous

I think I'm good; When I did it by myself I got x^2+2x-1=0

- mathmate

You have probably missed a (-1) from the second equation.

- just_one_last_goodbye

No problem ^_^ we believe everyone deserves an education but... it would be nice if you could get some qualified helper to help :) see... the people helping can give you a wrong answer but our QH help with a 100% step by step help and we can assure you that the answer will be correct (or your money back)

- anonymous

I don't have money for a QH

- imqwerty

don wrry :)

- just_one_last_goodbye

^ agreed ^_^

- anonymous

Okay, so I know it's not C or D

- anonymous

The one's would cancel out right?

- anonymous

which would leave B?

- mathmate

@just_one_last_goodbye
Are you suggesting that non QH will give a wrong answer and QH will not?

- imqwerty

\[-4x+1=y=2x^2-1\]\[-4x+1=2x^2-1\]can u find the answer now :)

- anonymous

?

- anonymous

@mathmate is B correct?

- mathmate

Follow what @imqwerty is working out for you.
We're using the same method.
@rosebud4612flvs

- imqwerty

ok
we know that-
\[y=-4x+1\]and also that\[y=2x^2-1\]
so -4x+1 and 2x^2-1 are both equal to y so they both are equal
so we can write\[-4x+1=2x^2-1\]did u understand this step?@rosebud4612flvs

- anonymous

Yes, I understand that step. What do I do next?

- anonymous

Do I have to combine the x's?

- just_one_last_goodbye

@mathmate I am stating that some non QH will probably give you a direct answer. and it might be wrong. Not all tho ^_^ Forgive me if I said it wrong

- anonymous

Okay so would I do 2x^2-1+(-4x+1)?

- anonymous

ugh

- anonymous

I think I did that wrong

- mathmate

@just_one_last_goodbye
whew! it's a little more clear!

- imqwerty

yes :) its correct so now u have this-\[-4x+1-(-4x+1)=2x^2 - 1 -(-4x+1)\] now open the brackets

- anonymous

okay so the first part cancels out

- anonymous

and that leaves me with 2(x^2−1+2x)

- anonymous

is that correct?

- imqwerty

yes and what about the right hand side

- anonymous

is it 2(x^2−1+2x)

- anonymous

would it be C?

- anonymous

x^2+2x-1=0

- imqwerty

no, what did u get on opening the bracket on the right hand side?

- anonymous

on the right hand side I got 2(x2−1+2x)

- imqwerty

yes that is correct :D
so now we have-
\[0=2(x^2-1+2x)\]opening the bracket u get-\[0=2(x^2)+2(-1)+2(2x)\]\[0=2x^2-2+4x\] thas ur answer :)

- anonymous

should it have been 2x^2-1+4x+1?

- anonymous

oh wait forget that

- anonymous

THANK YOU SO MUCH

- imqwerty

have u understood how we got the answer ?

- anonymous

It was correct :) and I understand it so much better now thank you

- imqwerty

np (:

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