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anonymous

  • one year ago

can I please get some help for this Algebra question?

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    I don't know why I am so confused with this question! Can someone please point me in the right direction?

  3. misty1212
    • one year ago
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    HI!!

  4. misty1212
    • one year ago
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    look at the graph what is \(f(-2)\)?

  5. anonymous
    • one year ago
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    \[(f+g)(a)=f(a)+g(a)\]\[(f-g)(a)=f(a)-g(a)\]\[(fg)(a)=f(a) \times g(a)\]\[(\frac{f}{g})(a)=\frac{f(a)}{g(a)} \space ; \space g(a)\neq 0\] Use these formulae and find the values from the graph

  6. anonymous
    • one year ago
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    so to find for your first part \[(f+g)(-2)=f(-2)+g(-2)\] you do it like that and the value of f(-2) and g(-2) may be obtained from the graph

  7. anonymous
    • one year ago
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    Okay but I how do I find that?

  8. anonymous
    • one year ago
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    F=-2,4? G=-2,0??

  9. anonymous
    • one year ago
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    yep! what are the y values for these points

  10. anonymous
    • one year ago
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    Think of your f(x) as y-values for the blue curve and g(x) as the y-values for the pink straight line so to find f(-2), we find the corresponding y value for the x value -2 on the blue curve and to find g(-2), we find the corresponding y value for the x value -2 on the pink straight line

  11. anonymous
    • one year ago
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    Hmm..okay..Now what? :/ still kind of confused

  12. anonymous
    • one year ago
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    you've found your \[f(-2)=4\]\[g(-2)=0\] Because -2,4 is a point lying on the blue curve and -2,0 is a point lying on the pink straight line

  13. anonymous
    • one year ago
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    basically u look at the x value, look for what value of y for that x we have a point lying on the curve and the line

  14. anonymous
    • one year ago
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    Ok do I add or subtract the numbers now? I think I remember learning that.

  15. anonymous
    • one year ago
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    \[(f+g)(-2)=f(-2)+g(-2)\] add them up :)

  16. anonymous
    • one year ago
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    -4 ?

  17. anonymous
    • one year ago
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    |dw:1444071199043:dw|

  18. anonymous
    • one year ago
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    Sorry got confused there. Now I get it...Lol. Ok for the next one, f(1)= 1 right?

  19. anonymous
    • one year ago
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    yep!

  20. anonymous
    • one year ago
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    and g(1)=3...so answer would be 4 also?

  21. anonymous
    • one year ago
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    No! this time you are subtracting! \[(f-g)(1)=f(1)-g(1)\]

  22. anonymous
    • one year ago
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    Ok I see that now lol So it would be 2

  23. anonymous
    • one year ago
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    Nevermind, -2!

  24. anonymous
    • one year ago
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    Good!

  25. anonymous
    • one year ago
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    Remember, for the next one you have to multiply!

  26. anonymous
    • one year ago
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    Yes I got 0 on that one..Now for D.

  27. anonymous
    • one year ago
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    yep!

  28. anonymous
    • one year ago
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    I got 1/3. Thanks SO much for your help. Have a great day!!

  29. anonymous
    • one year ago
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    correct!!

  30. anonymous
    • one year ago
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    An interesting thing to note here, if by chance your g(1) was 0, you would say that that your (f/g)(1) is not defined, as you can't divide by 0 \[(\frac{f}{g})(1)=\frac{f(1)}{g(1)}=\frac{f(1)}{0}\]

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