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im on this question

HI!!

i dont understand the problem the equation

you can do it without using \[A=Pe^{kt}\] if you like

Hello @misty1212

i dont know how to use that either lol

lets make it easier and call 1992 year zero

the beginning population is 222 that is your \(P\)

lol no, not the way they asked the question, that is your A

ok lol

\[P=1222e^{kt}\] but you don't know \(k\) that is what you have to find

typo but whatever

then since 9 years later it is 224 you can solve
\[\large224=222e^{9k}\] for \(k\)

so divide?

yeah divide
take the log
divide by 9

each sides by 9?

Please make sure to take the log before dividing by 9

i dont know the log

\[224=222e^{9k}\\
\frac{112}{111}=e^{9k}\\
\ln(1.009)=9k\\
k=\frac{\ln(1.09)}{9}\]

oh, if you don't know about logs you can's use this method

@misty1212 this is the same issue that cam up on the previous problem I was working with @ix.ty

Ok as I discussed before the natural logarithm is the INVERSE function of the exponential function.

it reverses another funtion
f(x)=-1/3x+1 youll but a y infront of the "fx"