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Defiance

  • one year ago

Will medal... 2x-9/x^2- x- 6 = A/x-3 + B/x+2 / as in fraction and ^2 as squared

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  1. misty1212
    • one year ago
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    HI!!

  2. misty1212
    • one year ago
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    partial fractions?

  3. Defiance
    • one year ago
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    Mhm.

  4. Defiance
    • one year ago
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    @ganeshie8

  5. Defiance
    • one year ago
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    Hello.?

  6. Defiance
    • one year ago
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    Ganeshie8, can you help?

  7. ganeshie8
    • one year ago
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    you may use the cover up method http://www.math-cs.gordon.edu/courses/ma225/handouts/heavyside.pdf

  8. ganeshie8
    • one year ago
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    \[\dfrac{2x-9}{x^2- x- 6} = \dfrac{A}{x-3} + \dfrac{B}{x+2} \] \[\dfrac{2x-9}{(x-3)(x+2)} = \dfrac{A}{x-3} + \dfrac{B}{x+2} \]

  9. ganeshie8
    • one year ago
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    Look at the "left hand side" expression. Cover up \(x-3\) and plugin \(x=3\), what do you get ?

  10. ganeshie8
    • one year ago
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    \[\dfrac{2x-9}{(x+2)} \] plugin x=3 above

  11. Defiance
    • one year ago
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    2(3)-9/5

  12. Defiance
    • one year ago
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    So, 1 / 5?

  13. ganeshie8
    • one year ago
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    (2(3)-9)/5 (6-9)/5 = ?

  14. Defiance
    • one year ago
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    1/5 and -3/5

  15. ganeshie8
    • one year ago
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    what 1/5 ?

  16. Defiance
    • one year ago
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    Wait sorry.

  17. Defiance
    • one year ago
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    i get -3/5 on both

  18. ganeshie8
    • one year ago
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    Lets work it step by step, shall we ? so far we have \(A=-\dfrac{3}{5}\)

  19. Defiance
    • one year ago
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    Yes.

  20. ganeshie8
    • one year ago
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    Next, cover up \(x+2\) and plugin \(x=-2\) in : \[\dfrac{2x-9}{(x-3)} \]

  21. Defiance
    • one year ago
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    13/5?

  22. ganeshie8
    • one year ago
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    Yep! you may double check with wolfram http://www.wolframalpha.com/input/?i=partial+fractions+%282x-9%29%2F%28x%5E2-+x-+6%29

  23. Defiance
    • one year ago
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    Thanks so much!

  24. ganeshie8
    • one year ago
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    yw

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