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jennyrlz
 one year ago
help!!!!!
Some college discrete math :3
jennyrlz
 one year ago
help!!!!! Some college discrete math :3

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jennyrlz
 one year ago
Best ResponseYou've already chosen the best response.0From the given functions defined from R to R, identify the bijective functions. f(x) = –3x + 4

jennyrlz
 one year ago
Best ResponseYou've already chosen the best response.0give me a sec, there are more choice ^.^

mathmate
 one year ago
Best ResponseYou've already chosen the best response.2This question requires an understanding of the meaning of the word "bijective". Once that's understood, the answer will be obvious. Bijection (according to Wiki) is "In mathematics, a bijection, bijective function or onetoone correspondence is a function between the elements of two sets, where every element of one set is paired with exactly one element of the other set, and every element of the other set is paired with exactly one element of the first set." If you google Bijective function, the heading gives a very nice visual illustration of exactly what bijection means.

jennyrlz
 one year ago
Best ResponseYou've already chosen the best response.0Fx=3x^2+7 Fx=(x+1)/(x+2) X^5+1=fx

jennyrlz
 one year ago
Best ResponseYou've already chosen the best response.0Ok thanks a lot I'll look into bike give xD

jennyrlz
 one year ago
Best ResponseYou've already chosen the best response.0I'm a little lost so I apreciate the help :)

mathmate
 one year ago
Best ResponseYou've already chosen the best response.2This is the description I was talking about. http://prntscr.com/8o4ozw In short, a bijective function has to satisfy both the vertical line test and horizontal line test, which you shoud have learned about in functions. From you understanding of the functions, you can sketch each and find out which one satisfies both the hor. and vert. line test. (also bear in mind that ALL functions should satisfy the vertical line test, so that cuts your work by two.)

jennyrlz
 one year ago
Best ResponseYou've already chosen the best response.0I found out thanks to you first reply :). Now I actually understand what I am doing ^.^

jennyrlz
 one year ago
Best ResponseYou've already chosen the best response.0If I have anymore questions I will ask you ^.^
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