is this a calculus problem?
yes calc ab.
I got 45,000
what is your equation for volume?
300x - x^3/2
1,200 = b^2 + 4bh hmm, have you done langrange multipliers?
langrange multipliers? Never heard of them. this is just applied min and max problems
V = b^2h ; A = b^2+4bh-1200 = 0 Vb = 2bh; L~Ab = L(2b+4h) Vh = b^2; L~Ah = L(4b) equating partials we have 4Lb = b^2, b=4L 2bh = 2Lb+4Lh bh-2Lh = Lb h(b-2L) = Lb h = Lb/(b-2L) = 2L ---------------- 3L^2 = 75 L=5 -------------- b=20, h=10 is what im getting ... if i did a proper langrange :)
i tried doing a min max setup but i wasnt getting anywhere useful, so i attempted the langrange
Okay that's long-range that's what we do as well. so because b=20 and h=10 the volume then we get lwh=20(10)(5)=1000?
we could take our volume in terms of b given that b^2+4bh-1200 = 0 h = (1200-b^2)(4b)^(-1) V = b^2(1200-b^2)(4b)^(-1) or V = (1200b -b^3)/4
Did you get the second 20 from b^2+4bh-1200 = 0
V = (1200b -b^3)/4 V' = (1200-3b^2)/4 = 0 1200-3b^2 = 0 1200 = 3b^2 400 = b^2 ; b=20
ohh ok i forgot to take the derivative of v.
no, i got b (the base) from the workings ... the base has a side length of 20
Okay, I understand now, thank you for helping me!