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tmagloire1
 one year ago
If 1,200 cm2 of material is available to make a box with a square base and an open top, find the maximum volume of the box in cubic centimeters. Answer to the nearest cubic centimeter without commas. For example, if the answer is 2,000 write 2000.
tmagloire1
 one year ago
If 1,200 cm2 of material is available to make a box with a square base and an open top, find the maximum volume of the box in cubic centimeters. Answer to the nearest cubic centimeter without commas. For example, if the answer is 2,000 write 2000.

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amistre64
 one year ago
Best ResponseYou've already chosen the best response.1is this a calculus problem?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1what is your equation for volume?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.11,200 = b^2 + 4bh hmm, have you done langrange multipliers?

tmagloire1
 one year ago
Best ResponseYou've already chosen the best response.0langrange multipliers? Never heard of them. this is just applied min and max problems

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1V = b^2h ; A = b^2+4bh1200 = 0 Vb = 2bh; L~Ab = L(2b+4h) Vh = b^2; L~Ah = L(4b) equating partials we have 4Lb = b^2, b=4L 2bh = 2Lb+4Lh bh2Lh = Lb h(b2L) = Lb h = Lb/(b2L) = 2L  3L^2 = 75 L=5  b=20, h=10 is what im getting ... if i did a proper langrange :)

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1i tried doing a min max setup but i wasnt getting anywhere useful, so i attempted the langrange

tmagloire1
 one year ago
Best ResponseYou've already chosen the best response.0Okay that's longrange that's what we do as well. so because b=20 and h=10 the volume then we get lwh=20(10)(5)=1000?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1we could take our volume in terms of b given that b^2+4bh1200 = 0 h = (1200b^2)(4b)^(1) V = b^2(1200b^2)(4b)^(1) or V = (1200b b^3)/4

tmagloire1
 one year ago
Best ResponseYou've already chosen the best response.0Did you get the second 20 from b^2+4bh1200 = 0

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1V = (1200b b^3)/4 V' = (12003b^2)/4 = 0 12003b^2 = 0 1200 = 3b^2 400 = b^2 ; b=20

tmagloire1
 one year ago
Best ResponseYou've already chosen the best response.0ohh ok i forgot to take the derivative of v.

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1no, i got b (the base) from the workings ... the base has a side length of 20

tmagloire1
 one year ago
Best ResponseYou've already chosen the best response.0Okay, I understand now, thank you for helping me!
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