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vera_ewing

  • one year ago

Pre-calculus question

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  1. vera_ewing
    • one year ago
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  2. vera_ewing
    • one year ago
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    @Directrix Help please!

  3. Directrix
    • one year ago
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    Sorry, my computer crashed, and I had to find my way back here. Look at the graph of y = x^2 - 7

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  4. Directrix
    • one year ago
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    That will give you some idea. Algebraically, y = x^2 - 7 can be written as y = 1*x^2 + 0x -7. The x coordinate of the vertex will give the line of symmetry using the formula, x = -b/(2a) where b = 0 and a = 2*1. So, x = 0.

  5. Directrix
    • one year ago
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    Is x = 0 the y-axis

  6. vera_ewing
    • one year ago
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    So how do we know which is symmetric?

  7. Directrix
    • one year ago
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    The parabola y = 1*x^2 + 0x -7 is symmetric about the line x = 0. Which option is that?

  8. vera_ewing
    • one year ago
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    C. the x axis

  9. Directrix
    • one year ago
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    No. The x-axis is horizontal.

  10. vera_ewing
    • one year ago
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    Oh so they y axis since it's vertical?

  11. Directrix
    • one year ago
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    Look at this picture.

  12. Directrix
    • one year ago
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    The y-axis because it has equation x = 0. Note on the picture that you could fold the parabola about the y-axis and the two parts would coincide.

  13. vera_ewing
    • one year ago
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    Ok thank you SO much!!

  14. Directrix
    • one year ago
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    You are welcome.

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