Pre-calculus question

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Pre-calculus question

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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@Directrix Help please!
Sorry, my computer crashed, and I had to find my way back here. Look at the graph of y = x^2 - 7
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That will give you some idea. Algebraically, y = x^2 - 7 can be written as y = 1*x^2 + 0x -7. The x coordinate of the vertex will give the line of symmetry using the formula, x = -b/(2a) where b = 0 and a = 2*1. So, x = 0.
Is x = 0 the y-axis
So how do we know which is symmetric?
The parabola y = 1*x^2 + 0x -7 is symmetric about the line x = 0. Which option is that?
C. the x axis
No. The x-axis is horizontal.
Oh so they y axis since it's vertical?
Look at this picture.
The y-axis because it has equation x = 0. Note on the picture that you could fold the parabola about the y-axis and the two parts would coincide.
Ok thank you SO much!!
You are welcome.

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